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anonymous
 5 years ago
find y' assuming that the equation deermines a differentiable function f such that y =f(x) y^2+1=x^2 3y
topic: implicit differentiation
anonymous
 5 years ago
find y' assuming that the equation deermines a differentiable function f such that y =f(x) y^2+1=x^2 3y topic: implicit differentiation

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0take the derivative of both sides wrt x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.02yy'=2x sec(y) +x^2 sec(y)tan(y)y'

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0solve for y' using algebra

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think it was \[y^2=x^2\sec(y)\] yes?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0howdy.... openstudys behaving bad tonight. i go to post and i get screenfreeze

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.02y y' = 2x3y + x^2 3 y' 2y y' x^2 3 y' = 6xy y'(2y 3x^2) = 6xy y' = 6xy/(2y3x^2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0y^2 + 1 = x^2 sec y satellite

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so i used the product rule for the x^2 sec y part?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you guys help me with the question i just posted

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes the product rule. and when you take the derivative of sec(y) make sure to put the y' at the end. i will write it out if you like let me kn ow

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i can do it thank you

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.02yy' = (2x)(secy)+(secy'tany')(x^2) is it correct?
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