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moongazer

  • 5 years ago

The solution set of 6 < 5x+7/2 < 11 is? Please answer clearly and explain the solution clearly and easy to understand. Thanks! (guaranteed medal for a good answer)

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  1. slaaibak
    • 5 years ago
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    subtract 7/2: 6 -3.5 < 5x + 3.5 - 3.5 < 11 - 3.5 2.5< 5x < 7.5 divide by 5: 2.5/5 < 5x/5 < 7.5/5 1/2 < x < 3/2

  2. moongazer
    • 5 years ago
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    i think the answer is (1,3) but i don't know why

  3. slaaibak
    • 5 years ago
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    No, it's not. I can guarantee you it's 1/2 < x < 3/2

  4. moongazer
    • 5 years ago
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    the choices are a. (1,3) b. (1,-3) c. (-1,3) d. no solution set what is the answer?

  5. slaaibak
    • 5 years ago
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    and you're sure the question is 6 < 5x+7/2 < 11 ?

  6. moongazer
    • 5 years ago
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    yup. i already have the solution but i can't understand what i wrote

  7. slaaibak
    • 5 years ago
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    http://www.wolframalpha.com/input/?i=6+%3C+5x%2B7%2F2+%3C+11+

  8. moongazer
    • 5 years ago
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    it is wrong it should be 5x+7 over 2 the 2 is the denominator of 5x+7

  9. moongazer
    • 5 years ago
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    not only of 7

  10. slaaibak
    • 5 years ago
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    oh, then people should use brackets... if it's 6<(5x+7)/2<11 multiply by 2: 12 < 5x+7 < 22 subtract 7: 5 <5x < 15 divide by 5: 1 < x < 3

  11. moongazer
    • 5 years ago
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    so the answer is (1,3)?

  12. slaaibak
    • 5 years ago
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    yes

  13. moongazer
    • 5 years ago
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    thanks! :)

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