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anonymous
 5 years ago
Find y' assuming that the equation determines a differentiable function f such that y= f(x)
sin^2 3y=x+y1
anonymous
 5 years ago
Find y' assuming that the equation determines a differentiable function f such that y= f(x) sin^2 3y=x+y1

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its implicit differentiation

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1yeah; but whats the equation?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes amistre that is correct

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its kind of assumed its sin^2 (3y) lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its unlikely to be sin^2(3) y

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1\[3y' 2\cos(3y)=1+y'\] \[6y'\cos(3y)y'=1\] \[y'(6\cos(3y)1)=1\] \[y' = \frac{1}{6\cos(3y)}\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1i did sin^2(3y) as tho it was simply sin(3y)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0alot of chain rules in that question

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its only once elecengineer

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1\[3y'.2(\sin(3y)).cos(3y)=1+y'\] \[y'.6\sin(3y)\cos(3y)y'= 1\] \[y'(6\sin(3y)\cos(3y)1)= 1\] \[y' = \frac{1}{6\sin(3y)\cos(3y)1}\] maybe

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0also, you couls apply double angle formula for sin to simplify the bottom :P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im trying to figure out what you did amistre

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0consider the LHS first, the derivative of the RHS is easy as

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so ( sin(3y) )^2 apply the chain rule , bring the power down in front , leave the inside of the bracket alone , reduce the power by one , then multiplt by the derivative of the inside

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so d/dx [ (sin(3y) ) ^2 ] = 2 sin(3y) [d/dx ( sin(3y) ) ]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0= 2 sin(3y) 3y' cos(3y)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1say you wanna derive: u^2; thats simple right? but: u = sin(v) and v = 3y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0when you differentiate sin(3y) you take the derivative of the inside with respect to x, and then change the sin function to a cos function

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the derivative of 3y with respect to x is 3 (dy/dx) = 3y'

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i get the 2(sin3y)(cos y) but not the 3y'

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1\[{du\over dx}={du\over dv}{dv\over dy}{dy\over dx}\] \[\frac{d(sin^2(3y))}{dx}=2sin(3y)*cos(3y)*3y'\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1you dont understand why we keep something hta tyou were taught to throw out

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1\[y = 2x^3 \rightarrow y' = 6x^2 x'\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1what did the \(y\) derive to? \(y'\) right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.13y derives to: \(3 y'\) \(5y^2\) derives to \(10y .y'\)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so the derivative of sin 3y is 3 sin 3y then 3y' cos 3y?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1you are used to throwing out the x' bit; but that is only because \(dx\over dx\)=1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i know that ist the trig function thats throwing me off

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1sin(3y) derives to 3y' cos(3y)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes...thats what confused me or should i say confuses

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the sin to cos? or the innards to the outside?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the innards the 3y inside the sin 3y

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the innards have a controling part in the function and have to be accounted for. They are the driving force that produces the output for the sin function

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the 'chain' rule is just accounting for all the inputs and outputs thru the equation that eah have a controling part

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok i guess i have to practice some more examples of them

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1try it on simple ones first: like, compound functions

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1interactmath.com can help; its a free practice math site

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0THANKS AGAIN SO MUCH AMISTRE AND ELECENGINEER

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you help me with the question i posted earlier today
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