anonymous
  • anonymous
Solve for x: log5^x-log5^2=2
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
is this \[log_5(x)-log_5(2)=2\]?
anonymous
  • anonymous
log 5x-log5 with the 2 at the top =2
anonymous
  • anonymous
if so combine the first two into one log as \[log_5(\frac{x}{2})=2\]\]

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anonymous
  • anonymous
ooh\[log(5) - log(2^2)=2\]
anonymous
  • anonymous
is that it?
anonymous
  • anonymous
the log5 and the x is superscript
anonymous
  • anonymous
x = [2 + 2log5]/log5
anonymous
  • anonymous
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anonymous
  • anonymous
did you see it
anonymous
  • anonymous
yeah...log_5(x/2) = 2, x/2 = 5^2, x = 50
anonymous
  • anonymous
thank you so much i have to learn how to write it like that
anonymous
  • anonymous
ah it was the first one i wrote. jamesm has the anwer
anonymous
  • anonymous
Thank you jamesm

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