## anonymous 5 years ago Solve for x: log5^x-log5^2=2

1. anonymous

is this $log_5(x)-log_5(2)=2$?

2. anonymous

log 5x-log5 with the 2 at the top =2

3. anonymous

if so combine the first two into one log as $log_5(\frac{x}{2})=2$\]

4. anonymous

ooh$log(5) - log(2^2)=2$

5. anonymous

is that it?

6. anonymous

the log5 and the x is superscript

7. anonymous

x = [2 + 2log5]/log5

8. anonymous

9. anonymous

did you see it

10. anonymous

yeah...log_5(x/2) = 2, x/2 = 5^2, x = 50

11. anonymous

thank you so much i have to learn how to write it like that

12. anonymous

ah it was the first one i wrote. jamesm has the anwer

13. anonymous

Thank you jamesm