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anonymous
 5 years ago
f(x) = cos(x  4)  8
find the inverse function of the function f
anonymous
 5 years ago
f(x) = cos(x  4)  8 find the inverse function of the function f

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0y= cos(x4) 8 cos(x4) = y+8 x4 =cos^{1}(y+8) x=4+ cos^{1}(y+8) so the inverse is 4+ cos^{1}(y+8)

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0y=cos(x4)8 (you should define a domain for this function that will make the function 1 to 1) y+8=cos(x4) cos^{1}(y+8)=x4 cos^{1}(y+8)+4=x f^{1}(x)=cos^{1}(x+8)+4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sin(cos1 1/2  sin1 squareroot 3 over 2) > how do you find the exact value of this??

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0cos^{1}(1/2)=a cosa=1/2 so a=pi/3 sin^{1}(sqrt{3}/2)=b sinb=sqrt{3}/2 so b=pi/3 sin(pi/3pi/3)=sin(0)=0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0cos(tan1 5/12  cos1 4/5) its multiple choice A) 7/13 B)63/65 c)52/65 d)13/24

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0let a be the first thing, b be the second and expand

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0also you can just put it in you calculator and then look at the fractions to see which one it is

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0thats the cheating way

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sin[pi/4 + x] = squareroot2(cos x + sin x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm suppose to establish the identity

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can express tan inverse in terms of cos inverse as tan^(1) (a/b)= cos^(1) (b/sqrt(a^2+b^2)) then use cos^(1) a + cos^(1) b formula to find the answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thanks shankvee!!!!! for all your help!
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