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anonymous
 5 years ago
The given equation involves a power of the variable. Find all real solutions of the equation.
8x^264=0
anonymous
 5 years ago
The given equation involves a power of the variable. Find all real solutions of the equation. 8x^264=0

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slaaibak
 5 years ago
Best ResponseYou've already chosen the best response.08(x^2  8)=0 x=2sqrt(2) or x = 2sqrt(2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay. can you show me what you did there? i'm having real trouble understanding this

slaaibak
 5 years ago
Best ResponseYou've already chosen the best response.0you first take out the common factor, which is 8: 8(x^2  8) = 0 then you use the difference of squares principle: 8(xsqrt(8))(x+sqrt(8))=0 then x = sqrt(8) or x= sqrt(8) simplified it's x=2sqrt(2) or x = 2sqrt(2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[8x^264=0\] add 64 to both sides \[8x^2=64\] divide both sides by 8 \[x^2=8\] take the square root \[x=\pm\sqrt{8}=\pm2\sqrt{2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think it's coming to me... i get where you get the common factor, then the difference of squares is giving me trouble... but i see what you are doing...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and since \[8=4\times 2\] \[\sqrt{8}=\sqrt{4}\times \sqrt{2}=2\sqrt{2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how do you know the 2(sqrt)2?? that is really throwing me for a loop.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0why isn't the square root of 8 just 2?
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