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anonymous

  • 5 years ago

lim n tends to infinity sum from k=0 to n (nCk)/ (n^k)(k+3) where nCk is n!/(k!(n-k)!) How do you express this sum as an integration?

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  1. Owlfred
    • 5 years ago
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    Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

  2. anonymous
    • 5 years ago
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    \[\frac{nCk}{ n^k (k+3)}\]?

  3. slaaibak
    • 5 years ago
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    Anyway you can give this more visually? I'm not 100% how the question looks like

  4. anonymous
    • 5 years ago
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    or

  5. anonymous
    • 5 years ago
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    \[\frac{nCk}{n^k}(k+3)\]

  6. anonymous
    • 5 years ago
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    k+3 is in the denominator

  7. anonymous
    • 5 years ago
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    ok

  8. anonymous
    • 5 years ago
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    easier way is start with the expansion (1+x)^n

  9. anonymous
    • 5 years ago
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    (1+x)^n = nC0 + nC1x + nC2 x^2 + .... nCk x^k + ... nCn x^n

  10. slaaibak
    • 5 years ago
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    \[\lim_{n \rightarrow \infty} \sum_{k=0}^{n} nCr (n^k)/(k+3) \] ?

  11. anonymous
    • 5 years ago
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    (1+n)^x = xC0 + xC1 n + xC2 n^2 + .... +xCk n^k + .... x Cx n^x

  12. anonymous
    • 5 years ago
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    n^k and k+3 are in the denominator numerator is only nCk

  13. anonymous
    • 5 years ago
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    well I know what the solution to the integral is, do you want to know that? maybe it would help you in deciding what the integral should look like. I'm not sure myself how to write the integral yet

  14. anonymous
    • 5 years ago
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    no i want what the integral is the answer is not really important...

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