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anonymous

  • 5 years ago

Can I factor a quadratic w/ a neg. x^2?

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  1. Owlfred
    • 5 years ago
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    Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

  2. amistre64
    • 5 years ago
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    you can, but its usually more effort than what its worth

  3. myininaya
    • 5 years ago
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    it depends on the quad

  4. anonymous
    • 5 years ago
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    I'm trying to solve a limit question and it has two quadratics undera radical, so I have to simplify. \[2+ x - x^2\]

  5. myininaya
    • 5 years ago
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    -x^2+x+2 -(x^2-x-2) -(x-2)(x+1)

  6. anonymous
    • 5 years ago
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    thank you -- I still can't figure out my limit, but thanks

  7. myininaya
    • 5 years ago
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    what is it?

  8. anonymous
    • 5 years ago
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    Lim as X goes to -Sqrt (2\[\lim x \rightarrow -1 \sqrt{2+x-x ^{2 } /x ^{2+4x+3}?}\]

  9. anonymous
    • 5 years ago
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    the denominator under the radical is x^2 +4x +3 I couldn't get it to read the right way in the editor. Thanks!

  10. myininaya
    • 5 years ago
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    wow that looks crazy

  11. myininaya
    • 5 years ago
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    \[\lim_{x \rightarrow -1} \sqrt{\frac{2+x-x^2}{x^2+4x+3}}\]

  12. myininaya
    • 5 years ago
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    is that right?

  13. anonymous
    • 5 years ago
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    yes! Its confusing to me

  14. myininaya
    • 5 years ago
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    \[\lim_{x \rightarrow -1}\sqrt{\frac{-1(x^2-x-2)}{(x+3)(x+1)}}=\lim_{x \rightarrow -1}\sqrt{\frac{-1(x+1)(x-2)}{(x+3)(x+1)}}\]

  15. myininaya
    • 5 years ago
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    x+1 's cancel right! :)

  16. myininaya
    • 5 years ago
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    \[\lim_{x \rightarrow -1}\sqrt{\frac{-1(x-2)}{x+3}}=\sqrt{\frac{-1(-1-2)}{-1+3}}=\sqrt{\frac{-1(-3)}{2}}=\sqrt{\frac{3}{2}}\]

  17. myininaya
    • 5 years ago
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    \[\sqrt{\frac{3}{2}}=\frac{\sqrt{3}}{\sqrt{2}}*\frac{\sqrt2}{\sqrt2}=\frac{\sqrt{6}}{2}\]

  18. anonymous
    • 5 years ago
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    yes -- got that great! Thats it! They have the answer as being sqare root of 6 /2. How do they get it in that form? Ah -- Thank you!!!!

  19. myininaya
    • 5 years ago
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    lol you didn't see what i typed until you got to the thank part lol right?

  20. anonymous
    • 5 years ago
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    Can I give you another tricky one?

  21. myininaya
    • 5 years ago
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    yes of course

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