anonymous
  • anonymous
Amistre64 can you help me again?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
\[22xe ^{x ^{2}}/\sqrt{e ^{x ^{2}}}\]
amistre64
  • amistre64
ok .... and this is a part of?
anonymous
  • anonymous
I need to find what it equals. I know what the answer is again, but again do not know how they got it.

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anonymous
  • anonymous
want a screen shot?
amistre64
  • amistre64
let me see the problem to get an better view of what you need; yes screen shot
anonymous
  • anonymous
1 Attachment
amistre64
  • amistre64
who is thinking up these things lol
anonymous
  • anonymous
I told you.,,it's the same guy that thinks he's smarter than me! Telling me I'm wrong all the time!! Humph!
amistre64
  • amistre64
\[\frac{22x.e^{x^2}}{\sqrt{e^{x^2 }}}\]
amistre64
  • amistre64
and you wanna know how they get their answer
anonymous
  • anonymous
yes
anonymous
  • anonymous
just index laws
amistre64
  • amistre64
lets clean it up some: \[\frac{22x.b}{\sqrt{b}}\] thats easier to see right? \[\frac{22x.b}{\sqrt{b}}*\frac{\sqrt{b}}{\sqrt{b}}=\frac{22x.b.b^{1/2}}{b}\] right?
amistre64
  • amistre64
does \({b\over b}\) cancel to 1?
amistre64
  • amistre64
leaves us: \[22x.b^{1/2}\] and we said \(b = e^{x^2}\) so rewrite it: \[22x.e^{(1/2)x^2}\]
anonymous
  • anonymous
yes but l;et me try to catch up...had to go away to give some medicine to my son. Let me scroll up to look at what you've typed.
anonymous
  • anonymous
You are the best...again thank you! You turned on my light bulb!
amistre64
  • amistre64
lol...youre welcome

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