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anonymous
 5 years ago
derivatieve of x^2 secy assuming that the equation determines a differentiable function f suht that y= f(x)
anonymous
 5 years ago
derivatieve of x^2 secy assuming that the equation determines a differentiable function f suht that y= f(x)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0technically cant be done

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it has to equal something

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x^2 secy must equal something

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x^2 (cosy)^1 = y^2 +1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0rewritting sec as cos^1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh i used the product rule

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(2x)(secy) but i dont know whts goes in the next bracket

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0because y depends on x , x^2 (cosy)^1 needs to be differenitated as product

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so then it'll be 2yy' = 2xsecy+x^2secytany*y'

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so LHS: let u= x^2 du/dx = 2x v= (cos(y))^1 dv/dx = 1 ( cos(y) )^2 * sin(y) (dy/dx)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so the LHS = 2x (cosy)^1 +(x^2sin(y) (sec(y))^2 ) dy/dx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and the RHS will equal 2y dy/dx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[2xsec(y) +x^2\sin(y)\sec^2(y)\frac{dy}{dx} = 2y \frac{dy}{dx}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok i understand thank you so much
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