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anonymous
 5 years ago
Find y' y^2 = x cos y assuming that the equation determines a differentiable function f such that y= f(x)
2yy' = (1)(cosy)  (siny)y'(x)
2yy'x(sin(y))y'=cosy
y'=cosy/(2yxsiny)
anonymous
 5 years ago
Find y' y^2 = x cos y assuming that the equation determines a differentiable function f such that y= f(x) 2yy' = (1)(cosy)  (siny)y'(x) 2yy'x(sin(y))y'=cosy y'=cosy/(2yxsiny)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just want to check my answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.02y dy/dx = x ( sin(y) dy/dx ) +cos(y) )

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the cos9y) at the end shouldnt be in the bracket

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0kk its the same as my answer just in terms of dy/dx so its correct :)?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you did make a mistake

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0an algebraic one, not a calculus one

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hmm not suprised not a fan of algebra

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0first line to second line

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you take a term from the RHS to the left, but dont change the sign

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its suppose to be positive when i take it over?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0also , just something notation wise, the first line 2yy' = (1)(cosy)  (siny)y'(x) , is badly written

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0like I mean I could get what you mean, but be aware of the order of the terms

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I know you mean to write xsin(y) y' for the last term

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but you have sin(y) y'(x) which can be interperated as sin(y) dy/dx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it might confuse yourself and the markers, so I would be careful about that in the future , order your terms to eliminate confusion

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh i do it step by step i wrote it that way on my next line sorry

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I dont care exactly what you do , I am just saying , I highly recommend you dont put y' and x next to eaach other in a term , especially with the x in a bracket, just remember that y'(x) is an alternative notation for dy/dx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok thanks for the advice i will remeber it for next time

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0alternatively , you can just write dy/dx when you use chain rules instead of y' , I rarely write y' , because it doesnt tell what the derivative is with respect to , and once you start to do multivariable calculus then you actually do have to write dy/dx , because y' is meaningless when you have multiple variables
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