anonymous
  • anonymous
Find the center, vertices, foci, and slope of the asymptotes for the hyperbola. (x-4)^2/16 - (y+4)^2/16 = 1
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
u can use wolfram and check he graph out
anonymous
  • anonymous
http://www.wolframalpha.com/input/?i=%28x-4%29^2%2F16++-++%28y%2B4%29^2%2F16+%3D+1
amistre64
  • amistre64
center(4,-4) verts are a distance of 4 from teh center to get: (8,-4) (0,-4)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

amistre64
  • amistre64
your bottoms ar ethe same whih means we get a distance of 4sqrt(2) for the foci foci = (4+4sqrt(2),-4) and (4-4sqrt(2),-4)
amistre64
  • amistre64
and slope of asymps are 1 and -1
anonymous
  • anonymous
jeezzz thanks again lol!!!

Looking for something else?

Not the answer you are looking for? Search for more explanations.