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anonymous
 5 years ago
Find y' sinsqrt y 3x = 2
assuming that the equation determines a differentiable function f such that y=f(x)
anonymous
 5 years ago
Find y' sinsqrt y 3x = 2 assuming that the equation determines a differentiable function f such that y=f(x)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you need to include brackets

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[1/2 (\sin y)^{1/2}(\cos y)y'3=0\] that is what i got but i dont know how to find y' now i.e. simplify

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its not clear what the actual question is

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sin \sqrt{y}  3x=0\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so sin( y^(1/2) ) 3x =2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(1/2)y^(1/2) dy/dx cos(y^(1/2) ) 3 =0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{1}{2\sqrt{y}} \frac{dy}{dx} \cos(\sqrt{y}) 3 =0 \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0why'd we get rid of the sin? in the first term

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0derivative of sin(f (x) ) = f'(x) cos(f(x) ) yes?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0differentiate the inside, multiply and channge the sin to cos

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok thank you i understand that was my fall down

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you were thinking of \[\frac{1}{2} \sin^2 (\sqrt{y} ) 3x =2 \] I think

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0or something similiar
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