im trying to do my math hw but i dont get it we are studying Quadratic functions abd the function is y=x^2-10x+2 help please :((

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im trying to do my math hw but i dont get it we are studying Quadratic functions abd the function is y=x^2-10x+2 help please :((

Mathematics
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Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!
First of all: Don't call yourself a math retard
lol

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Other answers:

haha (:
the first step is do not be negative lol
haha
what would you like to do with the "quady"
lol ok ok but can i get some gelp :/
*help
Second of all: Its just like solving an algebraic equation
i like gelp better
same lol
lol i know its the same but i juss dnt get it
so do you want to graph the "quady"?
silence satellite!
i dnt think im supposed to graph i think i juss needa find the vertex and coordinates :/ or maybe i am idk >.<
myininaya izzat you?
omg 465 so lame you are leaving me in the dust the more we find the better are graph will look lets start out with x-intercepts
to find x-intercepts, set y=0 and solve for x
x^2-10x+2=0
okk then what :o
now this is totally not factorble so you have to use the quady formula!
\[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]
satellite i was kidding you can talk lol
\[x=\frac{10 \pm \sqrt{10^2-4(1)(2)}}{2(1)}\]
sooo after tht wat next o.o
\[x=\frac{10 \pm \sqrt{100-8}}{2}=\frac{10 \pm \sqrt{92}}{2}=\frac{10 \pm \sqrt{4*23}}{2}\]
\[x=\frac{10 \pm 2\sqrt{23}}{2}=5 \pm \sqrt{23}\]
lordamercy \[x^2-10x+2=0\] \[x^2-20x=2\] \[(x-5)^2=-2+25=23\] \[x-5=\pm\sqrt{23}\] \[x=5\pm\sqrt{23}\]
so these two are where your graph is going to the intercept the x axis
satellite used completeing the square (which is used to proved the quady formula is the solution of the quady equation)
oops typo. second line should have been \[x^2-10x=-2\]
also it is nice to use when the middle coefficient is even so you do not have to simplify the radical, factor and cancel
yes that too
the quadratic formula forces a denominator on you but you see that there isn't one!
i will be quiet now
now lets take a break now from the hard stuff and see if we can find a y-intercept
to find the y-intercept, set x=0 and solve for y
y=0^2-10(0)+2=0-0+2=2
smhh i know you guys are gonna get mad but...i still dnt get it :[
i'm furious lol
i'll just take my frends answers in school tommorow lol
i was kidding
what part is getting you down?
i know lols
the whooooole thing D:
do you know the quadratic formula?
ax^2=bx+c?
*ax^2+bx+c
\[ax^2+bx+c=0\] -> quad equation \[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\] -> quad formula (solution to the quad equation)
mhmm :x
i thought it was just -b/2a
no
wow ok :/
bt anyway i go sleep now lols so ttyl
ok gn
gn ^_^

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