## anonymous 5 years ago im trying to do my math hw but i dont get it we are studying Quadratic functions abd the function is y=x^2-10x+2 help please :((

1. Owlfred

Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

2. anonymous

First of all: Don't call yourself a math retard

3. myininaya

lol

4. anonymous

haha (:

5. myininaya

the first step is do not be negative lol

6. anonymous

haha

7. myininaya

what would you like to do with the "quady"

8. anonymous

lol ok ok but can i get some gelp :/

9. anonymous

*help

10. anonymous

Second of all: Its just like solving an algebraic equation

11. myininaya

i like gelp better

12. anonymous

same lol

13. anonymous

lol i know its the same but i juss dnt get it

14. myininaya

so do you want to graph the "quady"?

15. myininaya

silence satellite!

16. anonymous

i dnt think im supposed to graph i think i juss needa find the vertex and coordinates :/ or maybe i am idk >.<

17. anonymous

myininaya izzat you?

18. myininaya

omg 465 so lame you are leaving me in the dust the more we find the better are graph will look lets start out with x-intercepts

19. myininaya

to find x-intercepts, set y=0 and solve for x

20. myininaya

x^2-10x+2=0

21. anonymous

okk then what :o

22. myininaya

now this is totally not factorble so you have to use the quady formula!

23. myininaya

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

24. myininaya

satellite i was kidding you can talk lol

25. myininaya

$x=\frac{10 \pm \sqrt{10^2-4(1)(2)}}{2(1)}$

26. anonymous

sooo after tht wat next o.o

27. myininaya

$x=\frac{10 \pm \sqrt{100-8}}{2}=\frac{10 \pm \sqrt{92}}{2}=\frac{10 \pm \sqrt{4*23}}{2}$

28. myininaya

$x=\frac{10 \pm 2\sqrt{23}}{2}=5 \pm \sqrt{23}$

29. anonymous

lordamercy $x^2-10x+2=0$ $x^2-20x=2$ $(x-5)^2=-2+25=23$ $x-5=\pm\sqrt{23}$ $x=5\pm\sqrt{23}$

30. myininaya

so these two are where your graph is going to the intercept the x axis

31. myininaya

satellite used completeing the square (which is used to proved the quady formula is the solution of the quady equation)

32. anonymous

oops typo. second line should have been $x^2-10x=-2$

33. anonymous

also it is nice to use when the middle coefficient is even so you do not have to simplify the radical, factor and cancel

34. myininaya

yes that too

35. anonymous

the quadratic formula forces a denominator on you but you see that there isn't one!

36. anonymous

i will be quiet now

37. myininaya

now lets take a break now from the hard stuff and see if we can find a y-intercept

38. myininaya

to find the y-intercept, set x=0 and solve for y

39. myininaya

y=0^2-10(0)+2=0-0+2=2

40. anonymous

smhh i know you guys are gonna get mad but...i still dnt get it :[

41. myininaya

i'm furious lol

42. anonymous

i'll just take my frends answers in school tommorow lol

43. myininaya

i was kidding

44. myininaya

what part is getting you down?

45. anonymous

i know lols

46. anonymous

the whooooole thing D:

47. myininaya

do you know the quadratic formula?

48. anonymous

ax^2=bx+c?

49. anonymous

*ax^2+bx+c

50. myininaya

$ax^2+bx+c=0$ -> quad equation $x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$ -> quad formula (solution to the quad equation)

51. anonymous

mhmm :x

52. anonymous

i thought it was just -b/2a

53. myininaya

no

54. anonymous

wow ok :/

55. anonymous

bt anyway i go sleep now lols so ttyl

56. myininaya

ok gn

57. anonymous

gn ^_^