anonymous
  • anonymous
im trying to do my math hw but i dont get it we are studying Quadratic functions abd the function is y=x^2-10x+2 help please :((
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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Owlfred
  • Owlfred
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anonymous
  • anonymous
First of all: Don't call yourself a math retard
myininaya
  • myininaya
lol

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anonymous
  • anonymous
haha (:
myininaya
  • myininaya
the first step is do not be negative lol
anonymous
  • anonymous
haha
myininaya
  • myininaya
what would you like to do with the "quady"
anonymous
  • anonymous
lol ok ok but can i get some gelp :/
anonymous
  • anonymous
*help
anonymous
  • anonymous
Second of all: Its just like solving an algebraic equation
myininaya
  • myininaya
i like gelp better
anonymous
  • anonymous
same lol
anonymous
  • anonymous
lol i know its the same but i juss dnt get it
myininaya
  • myininaya
so do you want to graph the "quady"?
myininaya
  • myininaya
silence satellite!
anonymous
  • anonymous
i dnt think im supposed to graph i think i juss needa find the vertex and coordinates :/ or maybe i am idk >.<
anonymous
  • anonymous
myininaya izzat you?
myininaya
  • myininaya
omg 465 so lame you are leaving me in the dust the more we find the better are graph will look lets start out with x-intercepts
myininaya
  • myininaya
to find x-intercepts, set y=0 and solve for x
myininaya
  • myininaya
x^2-10x+2=0
anonymous
  • anonymous
okk then what :o
myininaya
  • myininaya
now this is totally not factorble so you have to use the quady formula!
myininaya
  • myininaya
\[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]
myininaya
  • myininaya
satellite i was kidding you can talk lol
myininaya
  • myininaya
\[x=\frac{10 \pm \sqrt{10^2-4(1)(2)}}{2(1)}\]
anonymous
  • anonymous
sooo after tht wat next o.o
myininaya
  • myininaya
\[x=\frac{10 \pm \sqrt{100-8}}{2}=\frac{10 \pm \sqrt{92}}{2}=\frac{10 \pm \sqrt{4*23}}{2}\]
myininaya
  • myininaya
\[x=\frac{10 \pm 2\sqrt{23}}{2}=5 \pm \sqrt{23}\]
anonymous
  • anonymous
lordamercy \[x^2-10x+2=0\] \[x^2-20x=2\] \[(x-5)^2=-2+25=23\] \[x-5=\pm\sqrt{23}\] \[x=5\pm\sqrt{23}\]
myininaya
  • myininaya
so these two are where your graph is going to the intercept the x axis
myininaya
  • myininaya
satellite used completeing the square (which is used to proved the quady formula is the solution of the quady equation)
anonymous
  • anonymous
oops typo. second line should have been \[x^2-10x=-2\]
anonymous
  • anonymous
also it is nice to use when the middle coefficient is even so you do not have to simplify the radical, factor and cancel
myininaya
  • myininaya
yes that too
anonymous
  • anonymous
the quadratic formula forces a denominator on you but you see that there isn't one!
anonymous
  • anonymous
i will be quiet now
myininaya
  • myininaya
now lets take a break now from the hard stuff and see if we can find a y-intercept
myininaya
  • myininaya
to find the y-intercept, set x=0 and solve for y
myininaya
  • myininaya
y=0^2-10(0)+2=0-0+2=2
anonymous
  • anonymous
smhh i know you guys are gonna get mad but...i still dnt get it :[
myininaya
  • myininaya
i'm furious lol
anonymous
  • anonymous
i'll just take my frends answers in school tommorow lol
myininaya
  • myininaya
i was kidding
myininaya
  • myininaya
what part is getting you down?
anonymous
  • anonymous
i know lols
anonymous
  • anonymous
the whooooole thing D:
myininaya
  • myininaya
do you know the quadratic formula?
anonymous
  • anonymous
ax^2=bx+c?
anonymous
  • anonymous
*ax^2+bx+c
myininaya
  • myininaya
\[ax^2+bx+c=0\] -> quad equation \[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\] -> quad formula (solution to the quad equation)
anonymous
  • anonymous
mhmm :x
anonymous
  • anonymous
i thought it was just -b/2a
myininaya
  • myininaya
no
anonymous
  • anonymous
wow ok :/
anonymous
  • anonymous
bt anyway i go sleep now lols so ttyl
myininaya
  • myininaya
ok gn
anonymous
  • anonymous
gn ^_^

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