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First of all: Don't call yourself a math retard

lol

haha (:

the first step is do not be negative lol

haha

what would you like to do with the "quady"

lol ok ok but can i get some gelp :/

*help

Second of all: Its just like solving an algebraic equation

i like gelp better

same lol

lol i know its the same but i juss dnt get it

so do you want to graph the "quady"?

silence satellite!

myininaya izzat you?

to find x-intercepts, set y=0 and solve for x

x^2-10x+2=0

okk then what :o

now this is totally not factorble so you have to use the quady formula!

\[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]

satellite i was kidding you can talk lol

\[x=\frac{10 \pm \sqrt{10^2-4(1)(2)}}{2(1)}\]

sooo after tht wat next o.o

\[x=\frac{10 \pm \sqrt{100-8}}{2}=\frac{10 \pm \sqrt{92}}{2}=\frac{10 \pm \sqrt{4*23}}{2}\]

\[x=\frac{10 \pm 2\sqrt{23}}{2}=5 \pm \sqrt{23}\]

so these two are where your graph is going to the intercept the x axis

oops typo. second line should have been
\[x^2-10x=-2\]

yes that too

the quadratic formula forces a denominator on you but you see that there isn't one!

i will be quiet now

now lets take a break now from the hard stuff and see if we can find a y-intercept

to find the y-intercept, set x=0 and solve for y

y=0^2-10(0)+2=0-0+2=2

smhh i know you guys are gonna get mad but...i still dnt get it :[

i'm furious lol

i'll just take my frends answers in school tommorow lol

i was kidding

what part is getting you down?

i know lols

the whooooole thing D:

do you know the quadratic formula?

ax^2=bx+c?

*ax^2+bx+c

mhmm :x

i thought it was just -b/2a

no

wow ok :/

bt anyway i go sleep now lols so ttyl

ok gn

gn ^_^