im trying to do my math hw but i dont get it we are studying Quadratic functions abd the function is y=x^2-10x+2 help please :((

- anonymous

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- Owlfred

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- anonymous

First of all: Don't call yourself a math retard

- myininaya

lol

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## More answers

- anonymous

haha (:

- myininaya

the first step is do not be negative lol

- anonymous

haha

- myininaya

what would you like to do with the "quady"

- anonymous

lol ok ok but can i get some gelp :/

- anonymous

*help

- anonymous

Second of all: Its just like solving an algebraic equation

- myininaya

i like gelp better

- anonymous

same lol

- anonymous

lol i know its the same but i juss dnt get it

- myininaya

so do you want to graph the "quady"?

- myininaya

silence satellite!

- anonymous

i dnt think im supposed to graph i think i juss needa find the vertex and coordinates :/ or maybe i am idk >.<

- anonymous

myininaya izzat you?

- myininaya

omg 465 so lame you are leaving me in the dust
the more we find the better are graph will look
lets start out with x-intercepts

- myininaya

to find x-intercepts, set y=0 and solve for x

- myininaya

x^2-10x+2=0

- anonymous

okk then what :o

- myininaya

now this is totally not factorble so you have to use the quady formula!

- myininaya

\[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]

- myininaya

satellite i was kidding you can talk lol

- myininaya

\[x=\frac{10 \pm \sqrt{10^2-4(1)(2)}}{2(1)}\]

- anonymous

sooo after tht wat next o.o

- myininaya

\[x=\frac{10 \pm \sqrt{100-8}}{2}=\frac{10 \pm \sqrt{92}}{2}=\frac{10 \pm \sqrt{4*23}}{2}\]

- myininaya

\[x=\frac{10 \pm 2\sqrt{23}}{2}=5 \pm \sqrt{23}\]

- anonymous

lordamercy
\[x^2-10x+2=0\]
\[x^2-20x=2\]
\[(x-5)^2=-2+25=23\]
\[x-5=\pm\sqrt{23}\]
\[x=5\pm\sqrt{23}\]

- myininaya

so these two are where your graph is going to the intercept the x axis

- myininaya

satellite used completeing the square (which is used to proved the quady formula is the solution of the quady equation)

- anonymous

oops typo. second line should have been
\[x^2-10x=-2\]

- anonymous

also it is nice to use when the middle coefficient is even so you do not have to simplify the radical, factor and cancel

- myininaya

yes that too

- anonymous

the quadratic formula forces a denominator on you but you see that there isn't one!

- anonymous

i will be quiet now

- myininaya

now lets take a break now from the hard stuff and see if we can find a y-intercept

- myininaya

to find the y-intercept, set x=0 and solve for y

- myininaya

y=0^2-10(0)+2=0-0+2=2

- anonymous

smhh i know you guys are gonna get mad but...i still dnt get it :[

- myininaya

i'm furious lol

- anonymous

i'll just take my frends answers in school tommorow lol

- myininaya

i was kidding

- myininaya

what part is getting you down?

- anonymous

i know lols

- anonymous

the whooooole thing D:

- myininaya

do you know the quadratic formula?

- anonymous

ax^2=bx+c?

- anonymous

*ax^2+bx+c

- myininaya

\[ax^2+bx+c=0\] -> quad equation
\[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\] -> quad formula (solution to the quad equation)

- anonymous

mhmm :x

- anonymous

i thought it was just -b/2a

- myininaya

no

- anonymous

wow ok :/

- anonymous

bt anyway i go sleep now lols so ttyl

- myininaya

ok gn

- anonymous

gn ^_^

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