The given equation is either linear or equivalent to a linear equation. Solve the equation.
u/(u-(u+1)/2)=4

- anonymous

- katieb

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- anonymous

\[\frac{u}{\frac{u-(u+1)}{2}}=4\]?

- anonymous

looks like you have two fraction bars there.

- anonymous

yes satellite. haha

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## More answers

- myininaya

\[\frac{u}{u-\frac{(u+1)}{2}}=4\]

- anonymous

ok well first of all \[u-(u+1)=u-u-1=-1\]

- anonymous

so what you really have is
\[\frac{u}{\frac{-1}{2}}=4\]

- anonymous

dividing by one half same as multiplying by 2 so you get
\[-2u=4\]

- anonymous

divide by -2 to get
\[u=\frac{4}{-2}=-2\]

- anonymous

no. stop. sorry. wait a sec

- myininaya

lol

- anonymous

i stop

- anonymous

myininya has the correct problem shown

- myininaya

:)

- anonymous

well then my answer was the answer to a different question!

- anonymous

;(

- anonymous

using this site as a reference:http://www.wolframalpha.com/input/?i=u%2F%28u-%28u%2B1%29%2F2%29%3D4

- anonymous

any input is appreciated. i'm trying to figure out how to work it...

- anonymous

well that certainly is not a linear equation!

- myininaya

i would combine the fractions on bottom first

- anonymous

- anonymous

no chance. it is not linear

- anonymous

haha. that's how it's listed in my book :D

- anonymous

well it isn't look at the graph!

- anonymous

are you sure you typed it in correctly?

- anonymous

u = 2

- anonymous

yes. look at the link. that's exactly as it appears in my book :)

- anonymous

sure it isn't -2?

- anonymous

it's 2

- anonymous

aaaaaaaaaaaaaaaaaahhhhhhhhhhhhhhhhhhhhhhh

- anonymous

i see. simplify the compound fraction and you will get 2 lickety split

- myininaya

\[\frac{u}{\frac{2u-(u+1)}{2}}=u \div \frac{(2u-(u+1))}{2}=u \times \frac{2}{u-1}=\frac{2u}{u-1}\]

- anonymous

i don't see... :(

- myininaya

thats the left hand side

- myininaya

\[\frac{2u}{u-1}=4\]

- anonymous

where did you get 2u from?

- anonymous

in the very first step...

- anonymous

ok multiply top and bottom by 2 get
\[\frac{2u}{2u-(u+1)}\]

- anonymous

no pellet... lol. okay. i'm with you

- anonymous

clears the annoying 2 in the bottom of the denominator

- anonymous

now as we say in the math biz combine liked terms to get
\[\frac{2u}{u-1}\]

- myininaya

satellite cheated and did it the easy way

- anonymous

yeah. he thinks i know things and understand. :p

- myininaya

lol

- anonymous

so we have
\[\frac{2u}{u-1}=4\]
\[2u=4(u-1)\]
\[2u=4u-4\]
\[u = 2\] whew

- anonymous

waddya mean cheated? how else do you clear fractions?

- anonymous

wow. EASY!!! why was i stressing that?

- myininaya

lol i was kidding satellite

- anonymous

because it is math

- anonymous

i was taught to multiply the whole left side by the complex fraction u-(u+1/2) and do the same on the right...

- myininaya

math is the best because it is logic
english makes no sense

- anonymous

haha. taking math and english.... smh...

- anonymous

ooohhhh i see you subtracted in the denominator then inverted and multiplied. ok that works too.

- anonymous

if you are into long algebra. already annoyed that you can out-latex me! lol

- anonymous

gonna grab some food. will be back to annoy you guys in a little ;)
thank you both a lot!

- anonymous

now you are going to out algebra me too. not fair

- myininaya

lol no shorter ways are better than longer ways lol
i can only out latex you when you are drunk

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