## anonymous 5 years ago The given equation is either linear or equivalent to a linear equation. Solve the equation. u/(u-(u+1)/2)=4

1. anonymous

$\frac{u}{\frac{u-(u+1)}{2}}=4$?

2. anonymous

looks like you have two fraction bars there.

3. anonymous

yes satellite. haha

4. myininaya

$\frac{u}{u-\frac{(u+1)}{2}}=4$

5. anonymous

ok well first of all $u-(u+1)=u-u-1=-1$

6. anonymous

so what you really have is $\frac{u}{\frac{-1}{2}}=4$

7. anonymous

dividing by one half same as multiplying by 2 so you get $-2u=4$

8. anonymous

divide by -2 to get $u=\frac{4}{-2}=-2$

9. anonymous

no. stop. sorry. wait a sec

10. myininaya

lol

11. anonymous

i stop

12. anonymous

myininya has the correct problem shown

13. myininaya

:)

14. anonymous

15. anonymous

;(

16. anonymous

using this site as a reference: http://www.wolframalpha.com/input/?i=u%2F%28u-%28u%2B1%29%2F2%29%3D4

17. anonymous

any input is appreciated. i'm trying to figure out how to work it...

18. anonymous

well that certainly is not a linear equation!

19. myininaya

i would combine the fractions on bottom first

20. anonymous

The given equation is either linear or equivalent to a linear equation. Solve the equation. u/(u-(u+1)/2)=4

21. anonymous

no chance. it is not linear

22. anonymous

haha. that's how it's listed in my book :D

23. anonymous

well it isn't look at the graph!

24. anonymous

are you sure you typed it in correctly?

25. anonymous

u = 2

26. anonymous

yes. look at the link. that's exactly as it appears in my book :)

27. anonymous

sure it isn't -2?

28. anonymous

it's 2

29. anonymous

aaaaaaaaaaaaaaaaaahhhhhhhhhhhhhhhhhhhhhhh

30. anonymous

i see. simplify the compound fraction and you will get 2 lickety split

31. myininaya

$\frac{u}{\frac{2u-(u+1)}{2}}=u \div \frac{(2u-(u+1))}{2}=u \times \frac{2}{u-1}=\frac{2u}{u-1}$

32. anonymous

i don't see... :(

33. myininaya

thats the left hand side

34. myininaya

$\frac{2u}{u-1}=4$

35. anonymous

where did you get 2u from?

36. anonymous

in the very first step...

37. anonymous

ok multiply top and bottom by 2 get $\frac{2u}{2u-(u+1)}$

38. anonymous

no pellet... lol. okay. i'm with you

39. anonymous

clears the annoying 2 in the bottom of the denominator

40. anonymous

now as we say in the math biz combine liked terms to get $\frac{2u}{u-1}$

41. myininaya

satellite cheated and did it the easy way

42. anonymous

yeah. he thinks i know things and understand. :p

43. myininaya

lol

44. anonymous

so we have $\frac{2u}{u-1}=4$ $2u=4(u-1)$ $2u=4u-4$ $u = 2$ whew

45. anonymous

waddya mean cheated? how else do you clear fractions?

46. anonymous

wow. EASY!!! why was i stressing that?

47. myininaya

lol i was kidding satellite

48. anonymous

because it is math

49. anonymous

i was taught to multiply the whole left side by the complex fraction u-(u+1/2) and do the same on the right...

50. myininaya

math is the best because it is logic english makes no sense

51. anonymous

haha. taking math and english.... smh...

52. anonymous

ooohhhh i see you subtracted in the denominator then inverted and multiplied. ok that works too.

53. anonymous

if you are into long algebra. already annoyed that you can out-latex me! lol

54. anonymous

gonna grab some food. will be back to annoy you guys in a little ;) thank you both a lot!

55. anonymous

now you are going to out algebra me too. not fair

56. myininaya

lol no shorter ways are better than longer ways lol i can only out latex you when you are drunk