anonymous
  • anonymous
The given equation is either linear or equivalent to a linear equation. Solve the equation. u/(u-(u+1)/2)=4
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
\[\frac{u}{\frac{u-(u+1)}{2}}=4\]?
anonymous
  • anonymous
looks like you have two fraction bars there.
anonymous
  • anonymous
yes satellite. haha

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myininaya
  • myininaya
\[\frac{u}{u-\frac{(u+1)}{2}}=4\]
anonymous
  • anonymous
ok well first of all \[u-(u+1)=u-u-1=-1\]
anonymous
  • anonymous
so what you really have is \[\frac{u}{\frac{-1}{2}}=4\]
anonymous
  • anonymous
dividing by one half same as multiplying by 2 so you get \[-2u=4\]
anonymous
  • anonymous
divide by -2 to get \[u=\frac{4}{-2}=-2\]
anonymous
  • anonymous
no. stop. sorry. wait a sec
myininaya
  • myininaya
lol
anonymous
  • anonymous
i stop
anonymous
  • anonymous
myininya has the correct problem shown
myininaya
  • myininaya
:)
anonymous
  • anonymous
well then my answer was the answer to a different question!
anonymous
  • anonymous
;(
anonymous
  • anonymous
using this site as a reference:http://www.wolframalpha.com/input/?i=u%2F%28u-%28u%2B1%29%2F2%29%3D4
anonymous
  • anonymous
any input is appreciated. i'm trying to figure out how to work it...
anonymous
  • anonymous
well that certainly is not a linear equation!
myininaya
  • myininaya
i would combine the fractions on bottom first
anonymous
  • anonymous
The given equation is either linear or equivalent to a linear equation. Solve the equation. u/(u-(u+1)/2)=4
anonymous
  • anonymous
no chance. it is not linear
anonymous
  • anonymous
haha. that's how it's listed in my book :D
anonymous
  • anonymous
well it isn't look at the graph!
anonymous
  • anonymous
are you sure you typed it in correctly?
anonymous
  • anonymous
u = 2
anonymous
  • anonymous
yes. look at the link. that's exactly as it appears in my book :)
anonymous
  • anonymous
sure it isn't -2?
anonymous
  • anonymous
it's 2
anonymous
  • anonymous
aaaaaaaaaaaaaaaaaahhhhhhhhhhhhhhhhhhhhhhh
anonymous
  • anonymous
i see. simplify the compound fraction and you will get 2 lickety split
myininaya
  • myininaya
\[\frac{u}{\frac{2u-(u+1)}{2}}=u \div \frac{(2u-(u+1))}{2}=u \times \frac{2}{u-1}=\frac{2u}{u-1}\]
anonymous
  • anonymous
i don't see... :(
myininaya
  • myininaya
thats the left hand side
myininaya
  • myininaya
\[\frac{2u}{u-1}=4\]
anonymous
  • anonymous
where did you get 2u from?
anonymous
  • anonymous
in the very first step...
anonymous
  • anonymous
ok multiply top and bottom by 2 get \[\frac{2u}{2u-(u+1)}\]
anonymous
  • anonymous
no pellet... lol. okay. i'm with you
anonymous
  • anonymous
clears the annoying 2 in the bottom of the denominator
anonymous
  • anonymous
now as we say in the math biz combine liked terms to get \[\frac{2u}{u-1}\]
myininaya
  • myininaya
satellite cheated and did it the easy way
anonymous
  • anonymous
yeah. he thinks i know things and understand. :p
myininaya
  • myininaya
lol
anonymous
  • anonymous
so we have \[\frac{2u}{u-1}=4\] \[2u=4(u-1)\] \[2u=4u-4\] \[u = 2\] whew
anonymous
  • anonymous
waddya mean cheated? how else do you clear fractions?
anonymous
  • anonymous
wow. EASY!!! why was i stressing that?
myininaya
  • myininaya
lol i was kidding satellite
anonymous
  • anonymous
because it is math
anonymous
  • anonymous
i was taught to multiply the whole left side by the complex fraction u-(u+1/2) and do the same on the right...
myininaya
  • myininaya
math is the best because it is logic english makes no sense
anonymous
  • anonymous
haha. taking math and english.... smh...
anonymous
  • anonymous
ooohhhh i see you subtracted in the denominator then inverted and multiplied. ok that works too.
anonymous
  • anonymous
if you are into long algebra. already annoyed that you can out-latex me! lol
anonymous
  • anonymous
gonna grab some food. will be back to annoy you guys in a little ;) thank you both a lot!
anonymous
  • anonymous
now you are going to out algebra me too. not fair
myininaya
  • myininaya
lol no shorter ways are better than longer ways lol i can only out latex you when you are drunk

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