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anonymous

  • 5 years ago

Given sinθ = -3/4 and θ is in quadrant 4, find the following: cosθ tanθ sin (-θ) cos (-θ)

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  1. anonymous
    • 5 years ago
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  2. anonymous
    • 5 years ago
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    draw the picture

  3. anonymous
    • 5 years ago
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    sin is the opposite over the hypotenuse

  4. anonymous
    • 5 years ago
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    and use pythagorus to find the unknown side ( which turns out to be sqrt(7) )

  5. anonymous
    • 5 years ago
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    so now we have the triangle we can read of the values

  6. anonymous
    • 5 years ago
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    cos(theta) = sqrt(7) / 4

  7. anonymous
    • 5 years ago
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    What is sqrt? I haven't learned that...

  8. anonymous
    • 5 years ago
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    tan(theta ) = -3 / sqrt(7) , note: tan isneagtive in the 4th quadrant

  9. anonymous
    • 5 years ago
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    sqaure root lol

  10. anonymous
    • 5 years ago
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    \[\sqrt{7} ?\] , you must know

  11. anonymous
    • 5 years ago
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    Oh okay thank you lol I got confused

  12. anonymous
    • 5 years ago
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    ow, sin(-theta) - -sin(theta ) because sin is an odd function so sin(- theta ) = 3/4

  13. anonymous
    • 5 years ago
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    and cos(-theta) = cos(theta) , because cos is even , so cos(-theta) = sqrt(7) / 4

  14. anonymous
    • 5 years ago
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    thank you SOOOOO much! You're a big help. I really appreciate it!

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spraguer (Moderator)
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