## anonymous 5 years ago Given sinθ = -3/4 and θ is in quadrant 4, find the following: cosθ tanθ sin (-θ) cos (-θ)

1. anonymous

2. anonymous

draw the picture

3. anonymous

sin is the opposite over the hypotenuse

4. anonymous

and use pythagorus to find the unknown side ( which turns out to be sqrt(7) )

5. anonymous

so now we have the triangle we can read of the values

6. anonymous

cos(theta) = sqrt(7) / 4

7. anonymous

What is sqrt? I haven't learned that...

8. anonymous

tan(theta ) = -3 / sqrt(7) , note: tan isneagtive in the 4th quadrant

9. anonymous

sqaure root lol

10. anonymous

$\sqrt{7} ?$ , you must know

11. anonymous

Oh okay thank you lol I got confused

12. anonymous

ow, sin(-theta) - -sin(theta ) because sin is an odd function so sin(- theta ) = 3/4

13. anonymous

and cos(-theta) = cos(theta) , because cos is even , so cos(-theta) = sqrt(7) / 4

14. anonymous

thank you SOOOOO much! You're a big help. I really appreciate it!