A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
Write the expression sin(tan^1)x) as an algebraic expression in x (without trig or inverse trig functions).
A. (sqrt (1+x^2))/ (x)
B. (1) / (sqrt (1+x^2))
C. (x) / (sqrt (1x^2))
D. (x) / (sqrt (1+x^2))
E. (1) / (sqrt (1x^2))
anonymous
 5 years ago
Write the expression sin(tan^1)x) as an algebraic expression in x (without trig or inverse trig functions). A. (sqrt (1+x^2))/ (x) B. (1) / (sqrt (1+x^2)) C. (x) / (sqrt (1x^2)) D. (x) / (sqrt (1+x^2)) E. (1) / (sqrt (1x^2))

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0make a triangle... the ans will be obvious. it is opp/hyp so it is x/(x^2+1)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ah a triangle! Thank you!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes a triangle. label "opposite" side x and adjacent side 1 since the tangent is x = x/1 use pythatoras to find the hypotenuse which will be \[\sqrt{1+x^2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then \[sin(tan^{1}(x))=\frac{x}{\sqrt{1+x^2}}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that being opposite over hypotenuse

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and by the same triangle \[cos(tan^{1}(x))=\frac{1}{\sqrt{1+x^2}}\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.