Can you check my answers? File attached (only 9 problems)

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Can you check my answers? File attached (only 9 problems)

Mathematics
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1 Attachment
checking now... 37 38 right
38 39 are right

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Other answers:

first one is wrong
37 is not right lol
41 is wrong
fail... 3+2 = 5
^for 37
the last question is actually very easy
ok sorry i multiplied for some reason :P
41?
answer to 45 is just "3"
nvm i know how to do 41 and how did u get 3?
g(x) = -2f(x-1) + 5 , this given
now , g(3) , just means go the function and g , and everywhere you see an x , replace it with a 3
ie , g(3) = -2 f(3-1) + 5 // by subbing int the above
g(3) = -2f(2) + 5
but we were told f(2) = 1
the answer for 45 is 3
g(3) = -2 +5 = 3
ok i see thanks! so is everything else besades 41 correct?
lol I was too slow elecengineer (and I'm assuming that you're in electrical engineering.. which I am too haha)
no, 37 is wrong
well ya besides that?
37 should be +5
how do you do 42?
confirmed 44 righttttt
42 is inverse just switch the y and x around lemme see
so you have y=x+3 make it so that it is x=y+3
then you'll have y=x-3 where y=h^(-1)x
so whats the answer?
x-3
lol
oh ok and is the answer to 41 7x^3+36x^2+54x+28?
hello?
37. h(2+a) = (2+a)+3 = 5+a 38. correct 39. correct 40. correct\[41.f(x+h)-f(x) = [(x+h)^{3}+1]-(x ^{3}+1)\]\[=x ^{3}+h ^{3}+3x ^{2}h+3xh ^{2}+1-x ^{3}-1\]\[=h ^{3}+3x ^{2}h+3xh ^{2}\] \[42. h ^{-1}(x)=1/(x+3)\] \[43. f(x)*g(x) = (x ^{3}+1)(x ^{2}-2)\]\[=x ^{5}-2x ^{3}+x ^{2}-2\] 44. correct 45. g(x) = -2f(x-1)+5 g(3) = -2f(3-1)+5 = -2f(2)+5 = -2*1+5 f(2)=1 = -2+5 = 3

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