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anonymous
 5 years ago
how can we find a normal vector from the equ of aplane give reasons of ur ans
anonymous
 5 years ago
how can we find a normal vector from the equ of aplane give reasons of ur ans

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0rearrange the eqn of a plane in the form ax +by + cz +d=0 the normal vector is <a,b,c>

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0give reasons why we do this

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0suppose any known vector k, and normal vector n then the eqn of the plane is (rk).n = 0 if you expand this, youll see the coefficients of x, y, z in cartesian form are the direction ratios of the normal vector

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0PS : k is the position vector of a known pt on the plane

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what are direction ratios??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0consider a plane equation in its primary form (rk).n=0 (where n>normal vector & k> is the position vector of the plane) and when u expand this using simple dot product then finally u will get that coefficients of x,y,z gives u the dierection ratios direction ratios are the ratio of the magnitude of vector in one direction to the magnitude in the resultant direction.
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