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anonymous

  • 5 years ago

how can we find a normal vector from the equ of aplane give reasons of ur ans

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  1. anonymous
    • 5 years ago
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    rearrange the eqn of a plane in the form ax +by + cz +d=0 the normal vector is <a,b,c>

  2. anonymous
    • 5 years ago
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    give reasons why we do this

  3. anonymous
    • 5 years ago
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    suppose any known vector k, and normal vector n then the eqn of the plane is (r-k).n = 0 if you expand this, youll see the coefficients of x, y, z in cartesian form are the direction ratios of the normal vector

  4. anonymous
    • 5 years ago
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    PS : k is the position vector of a known pt on the plane

  5. anonymous
    • 5 years ago
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    what are direction ratios??

  6. anonymous
    • 5 years ago
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    consider a plane equation in its primary form (r-k).n=0 (where n->normal vector & k-> is the position vector of the plane) and when u expand this using simple dot product then finally u will get that coefficients of x,y,z gives u the dierection ratios direction ratios are the ratio of the magnitude of vector in one direction to the magnitude in the resultant direction.

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