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anonymous
 5 years ago
Find the answer. B needs to be by itself. (a+b)/2c = b+d
anonymous
 5 years ago
Find the answer. B needs to be by itself. (a+b)/2c = b+d

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You want to solve for \(b\)?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0And show your work, please!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0OK. Start by multiplying both sides by \(2c\) to get rid of the denominator. So, we will have \(a+b=(b+d)2c\). Opening the parenthesis gives \(a+b=2bc+2cd\). Since we're trying to solve for \(b\), we should combine all terms with \(b\) in one side and everything else on the other side. That gives \(b2bc=2cda\). Take \(b\) as a common factor in the left hand side, you get \(b(12c)=2cda\). Finally divide both sides by \(12c\) you get \(b=\frac{2cda}{12c}\).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0b = (a2*c*d)/(2*c1)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0cross multiply then a+b =2c(b+d) then take b containing term on one side and rest on other side so b(2c1) = a2cd now divide both side by (2c1) so u get b= (a2cd)/(2c1)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(a+b)/2c = b=d 2bc + 2cd = a + b .................. (multiply both side by 2c) 2bc  b = a  2cd ...................... (changing side of b) b ( 2c  1) = a  2cd b = (a2cd) / (2c  1)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Everyone had good answers! Thanks, and I agree with them.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well they all are actually the same :)
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