## anonymous 5 years ago Find the answer. B needs to be by itself. (a+b)/2c = b+d

1. anonymous

You want to solve for $$b$$?

2. anonymous

yes!

3. anonymous

4. anonymous

OK. Start by multiplying both sides by $$2c$$ to get rid of the denominator. So, we will have $$a+b=(b+d)2c$$. Opening the parenthesis gives $$a+b=2bc+2cd$$. Since we're trying to solve for $$b$$, we should combine all terms with $$b$$ in one side and everything else on the other side. That gives $$b-2bc=2cd-a$$. Take $$b$$ as a common factor in the left hand side, you get $$b(1-2c)=2cd-a$$. Finally divide both sides by $$1-2c$$ you get $$b=\frac{2cd-a}{1-2c}$$.

5. anonymous

b = (a-2*c*d)/(2*c-1)

6. anonymous

cross multiply then a+b =2c(b+d) then take b containing term on one side and rest on other side so b(2c-1) = a-2cd now divide both side by (2c-1) so u get b= (a-2cd)/(2c-1)

7. anonymous

(a+b)/2c = b=d 2bc + 2cd = a + b .................. (multiply both side by 2c) 2bc - b = a - 2cd ...................... (changing side of b) b ( 2c - 1) = a - 2cd b = (a-2cd) / (2c - 1)

8. anonymous