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anonymous
 5 years ago
Calculate Tan 0
anonymous
 5 years ago
Calculate Tan 0

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Using Triangle with angle 0 ,Hypotenuse 12, and bottom Leg 10

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Use pythagoras to find opposite leg 12 squared  10 squres = 44 so root 44 therefore tan theta = (in your calculator) INV TAN root44/10

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I am assuming it is tan theta not tan zero as that would be something altogether different.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sin0=0 sin30=1/2 sin60=sqrt3/2 sin90=1 cos0=1 cos30=sin60=sqrt3/2 cos60=sin30=1/2 cos90=0 tan0=sin0/cos0=0 tan30=1/sqrt3 tan60=sqrt3 tan90=sin90/cos90=1/0\[\infty\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think this can be helpful to you

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0tan90=sin90/cos90=1/0=∞

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Korcan, you have posted some pretty good things here but I still think we are looking at theta as opposed to zero.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Look at info regarding hypotenuse and leg length

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is 0 in radians or degree

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0tan 0 = sin 0 / cos 0 = 0/1= 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The length of the legs are: hypotenuse=12 , bottom leg=10. For the 3rd leg we have:\[\sqrt{12^210^2} = \sqrt{44}\] \[\tan(\theta)=\frac{OppositeLegLength}{AdjacentLegLength}\] So, if theta is opposite the 3rd leg , then:\[\tan(\theta)=\sqrt{44}/10\] Otherwise, theta is opposite the bottom leg, then: \[\tan(\theta)=10/\sqrt{44}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Going further  If theta is opposite the 3rd leg, then: \[\tan(\theta)=\frac{\sqrt{44}}{10} = \frac{\sqrt{4*11}}{10}=\frac{\sqrt{4}\sqrt{11}}{10}=\frac{2\sqrt{11}}{10}=\frac{\sqrt{11}}{5}\] Otherwise, theta is opposite the bottom leg, then: \[\tan(\theta)=\frac{5}{\sqrt{11}}\] If your original problem had a diagram, you can see whether theta is opposite the bottom leg or opposite the 3rd leg .
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