## anonymous 5 years ago Calculate Tan 0

1. watchmath

0

2. anonymous

Using Triangle with angle 0 ,Hypotenuse 12, and bottom Leg 10

3. anonymous

Use pythagoras to find opposite leg 12 squared - 10 squres = 44 so root 44 therefore tan theta = (in your calculator) INV TAN root44/10

4. anonymous

I am assuming it is tan theta not tan zero as that would be something altogether different.

5. anonymous

tan0=sin0/cos0=0

6. anonymous

sin0=0 sin30=1/2 sin60=sqrt3/2 sin90=1 cos0=1 cos30=sin60=sqrt3/2 cos60=sin30=1/2 cos90=0 tan0=sin0/cos0=0 tan30=1/sqrt3 tan60=sqrt3 tan90=sin90/cos90=1/0$\infty$

7. anonymous

i think this can be helpful to you

8. anonymous

tan90=sin90/cos90=1/0=∞

9. anonymous

Korcan, you have posted some pretty good things here but I still think we are looking at theta as opposed to zero.

10. anonymous

hmm

11. anonymous

Look at info regarding hypotenuse and leg length

12. anonymous

is 0 in radians or degree

13. anonymous

tan 0 = sin 0 / cos 0 = 0/1= 0

14. anonymous

The length of the legs are: hypotenuse=12 , bottom leg=10. For the 3rd leg we have:$\sqrt{12^2-10^2} = \sqrt{44}$ $\tan(\theta)=\frac{OppositeLegLength}{AdjacentLegLength}$ So, if theta is opposite the 3rd leg , then:$\tan(\theta)=\sqrt{44}/10$ Otherwise, theta is opposite the bottom leg, then: $\tan(\theta)=10/\sqrt{44}$

15. anonymous

Going further - If theta is opposite the 3rd leg, then: $\tan(\theta)=\frac{\sqrt{44}}{10} = \frac{\sqrt{4*11}}{10}=\frac{\sqrt{4}\sqrt{11}}{10}=\frac{2\sqrt{11}}{10}=\frac{\sqrt{11}}{5}$ Otherwise, theta is opposite the bottom leg, then: $\tan(\theta)=\frac{5}{\sqrt{11}}$ If your original problem had a diagram, you can see whether theta is opposite the bottom leg or opposite the 3rd leg .