Calculate Tan 0

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Calculate Tan 0

Mathematics
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Using Triangle with angle 0 ,Hypotenuse 12, and bottom Leg 10
Use pythagoras to find opposite leg 12 squared - 10 squres = 44 so root 44 therefore tan theta = (in your calculator) INV TAN root44/10

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Other answers:

I am assuming it is tan theta not tan zero as that would be something altogether different.
tan0=sin0/cos0=0
sin0=0 sin30=1/2 sin60=sqrt3/2 sin90=1 cos0=1 cos30=sin60=sqrt3/2 cos60=sin30=1/2 cos90=0 tan0=sin0/cos0=0 tan30=1/sqrt3 tan60=sqrt3 tan90=sin90/cos90=1/0\[\infty\]
i think this can be helpful to you
tan90=sin90/cos90=1/0=∞
Korcan, you have posted some pretty good things here but I still think we are looking at theta as opposed to zero.
hmm
Look at info regarding hypotenuse and leg length
is 0 in radians or degree
tan 0 = sin 0 / cos 0 = 0/1= 0
The length of the legs are: hypotenuse=12 , bottom leg=10. For the 3rd leg we have:\[\sqrt{12^2-10^2} = \sqrt{44}\] \[\tan(\theta)=\frac{OppositeLegLength}{AdjacentLegLength}\] So, if theta is opposite the 3rd leg , then:\[\tan(\theta)=\sqrt{44}/10\] Otherwise, theta is opposite the bottom leg, then: \[\tan(\theta)=10/\sqrt{44}\]
Going further - If theta is opposite the 3rd leg, then: \[\tan(\theta)=\frac{\sqrt{44}}{10} = \frac{\sqrt{4*11}}{10}=\frac{\sqrt{4}\sqrt{11}}{10}=\frac{2\sqrt{11}}{10}=\frac{\sqrt{11}}{5}\] Otherwise, theta is opposite the bottom leg, then: \[\tan(\theta)=\frac{5}{\sqrt{11}}\] If your original problem had a diagram, you can see whether theta is opposite the bottom leg or opposite the 3rd leg .

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