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  • 5 years ago

1) A diver shines a flashlight upward from beneath the water at an angle of 46.5 degrees to the vertical. At what angle does the light leave the water?

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  1. anonymous
    • 5 years ago
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    \[\mu=\frac{\sin \theta _{i}}{\sin \theta _{r}}=>\theta _{i}=\sin^{-1} (\mu \sin \theta _{r})=\sin^{-1} (1.33\times \sin 46.5)=74.7degrees\]

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