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anonymous
 5 years ago
solve for x:
log$2(x+1)+log$2(3x5)=log$2(5x3)+2
anonymous
 5 years ago
solve for x: log$2(x+1)+log$2(3x5)=log$2(5x3)+2

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Owlfred
 5 years ago
Best ResponseYou've already chosen the best response.0Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(x+1)(3x5) = 4(5x3)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay......can you keep going?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.03x^2 2x 5 = 20x 12 3x^2  22x +7 = 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0does the last line factor into (x7)(3x1)?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x = 7 or 1/3 now substitute both these values into ur initial eqn to double check

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay and on the first line you wrote 4(5x3).....how did you get the four? 2^2?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes 2 can be written as log 4 to base 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and then we use log a + log b =log (ab)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thanks you. thanks were i kept going wrong. The solutions both work. :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can i ask one more thing? if you are solving for x and you take the square root to isolate x, do you include both the positive and negative answers?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0like lets say x^2 = k then x = k AND k

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0in some special situations we can neglect the negative answer..bt generally it is essential to consider both
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