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anonymous

  • 5 years ago

Write the standard form of the hyperbola that has a center of (0, 0), vertices at (3, 0) and (-3, 0), and slopes of the asymptotes are 4/3 and -4/3.

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  1. anonymous
    • 5 years ago
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    see ill tell u the method

  2. anonymous
    • 5 years ago
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    the hyperbola is of the form x^2/a^2 + y^2/b^2 = 1

  3. anonymous
    • 5 years ago
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    a = 3 as the vertices are at 3,0 and -3,0

  4. anonymous
    • 5 years ago
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    if the angle bw asymptotes is t, the eccentricity e = sec (2t)

  5. anonymous
    • 5 years ago
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    and we know b^2/a^2 = e^2 - 1

  6. anonymous
    • 5 years ago
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    so find b frm this..get it?

  7. anonymous
    • 5 years ago
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    b is 72/25

  8. anonymous
    • 5 years ago
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    get it??????

  9. amistre64
    • 5 years ago
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    that part tends to get me; why would 'b' not be 4?

  10. anonymous
    • 5 years ago
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    yeah i got it i think

  11. anonymous
    • 5 years ago
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    what is the actual equation though

  12. amistre64
    • 5 years ago
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    x^2 y^2 --- - ---- = 1 right? 9 b^2

  13. anonymous
    • 5 years ago
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    so there is no b^2?

  14. amistre64
    • 5 years ago
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    im thinking b^2 = 16 .... but i could be wrong

  15. amistre64
    • 5 years ago
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    hims smart about this stuff which makes me doubt my b^2 :)

  16. anonymous
    • 5 years ago
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    yeah ur right amistre...

  17. amistre64
    • 5 years ago
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    yay!! im right

  18. anonymous
    • 5 years ago
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    im lovesick 2 amistre..bound to go wrong smwhere..lol

  19. amistre64
    • 5 years ago
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    lol trees pic is cute...

  20. anonymous
    • 5 years ago
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    y du think i jumped onto her question? dont mind tree..compliments

  21. anonymous
    • 5 years ago
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    :)

  22. amistre64
    • 5 years ago
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    i thought maybe to give her an answer :)

  23. anonymous
    • 5 years ago
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    yes..bt with ulterior motives 2..lol

  24. anonymous
    • 5 years ago
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    lol :))))))))))))))))

  25. anonymous
    • 5 years ago
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    never knew beautiful people could give parentheses life with their smiles..;)

  26. anonymous
    • 5 years ago
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    lol thanks

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