Write the standard form of the hyperbola that has a center of (0, 0), vertices at (3, 0) and (-3, 0), and slopes of the asymptotes are 4/3 and -4/3.

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Write the standard form of the hyperbola that has a center of (0, 0), vertices at (3, 0) and (-3, 0), and slopes of the asymptotes are 4/3 and -4/3.

Mathematics
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see ill tell u the method
the hyperbola is of the form x^2/a^2 + y^2/b^2 = 1
a = 3 as the vertices are at 3,0 and -3,0

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Other answers:

if the angle bw asymptotes is t, the eccentricity e = sec (2t)
and we know b^2/a^2 = e^2 - 1
so find b frm this..get it?
b is 72/25
get it??????
that part tends to get me; why would 'b' not be 4?
yeah i got it i think
what is the actual equation though
x^2 y^2 --- - ---- = 1 right? 9 b^2
so there is no b^2?
im thinking b^2 = 16 .... but i could be wrong
hims smart about this stuff which makes me doubt my b^2 :)
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