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anonymous
 5 years ago
kk then, what is deriative??
anonymous
 5 years ago
kk then, what is deriative??

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0study of how a function change, or tangent line

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3derivative is what is used to describe how one thing changes with respect to another

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3in the equation: y = 3x+2, the rate at which y changes with respect to x is '3'

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3for every change in 'x', 'y' changes by 3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hmm then u mean 2y=3x+3+2 ??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0or 2y=6x+2?? (the 2 is const in this equetion?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3if you multiply the left by 2 the rights gotta be multiplied by 2 as well

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3thats more of a scaling notion

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3the derivative has to do with the change in y with respect to x when there is 'no' change in x

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3\[\lim_{h > 0}\frac{(f(x+h)f(x)}{(x+h)(x)}\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3the derivative of: 3x+2 is then (3(x+h)+2)  (3x+2)  ; when h=0 x+hx

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.33x+3h+2 3x2  ; when h=0 h 3h  ; when h=0 h 3 ; when h=0

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3so the rate of change of a linear function is just the slope of the line

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3the rate of change at any given point of a quadratic function is the slope of the line at a given point that is defined as the lim{h >0} (f(x+h)f(x)//h)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3x^2+x3 ; how fast is y changing when x = 4?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you answer it? i think i can'T do it yet

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3\[\lim_{h > 0}\frac{ [(x+h)^2 +(x+h)3][x^2+x3]}{x+hx}\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3\[\lim{x^2+h^2 +2xh +x+h3x^2x3 \over h}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0getting my pencil and notebook

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3that last 3 shoud be +3

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3\[(x^2x^2)+(xx)+(3+3)+(2xh+h) \over h\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3yes, i missed the ^2 on the h; you are roght

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3\[\lim_{h \rightarrow 0}\left({h^2\over h}+{2xh\over h}\right)\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3and I think we dropped an h someplace in the writing

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes why don'T we do it one a more simple func??

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3\[\lim_{h >0}({2xh\over h}+{h\over h}+{h^2\over h})\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3the simple function was the linear lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3now when h=0 we get the equation of the derivative: 2x+1

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3at x=4; y is changing at a rate of 9 with respect to each x

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3the quick way after being taught all the limit definitions and the long way; is to use the power rule: x^2 +x 3 > 2x +1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hmm ^^ so that can we use this for another thing?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0with another func i mean

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(don't got the power rule can you explain?)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3yes; the derivative of position tells you velocity at a given point; the derivative of velocity tells you the acceleration at any given point

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3the power rule is just the 'pattern' that occurs from doing derivatives the long way..

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3\[Cx^n \implies C*nx^{n1} \] \[5x^3 \implies 5*3x^{31} \iff 15x^2\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3which way would you do derivatives? the limit way or the power rule?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3\[\begin{array}c 5x^4&+x^2&4x^0\\20x^3&+2x&+0\end{array}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hmm i think limit way

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3ok; do that the limit way... \[\frac{[5(x+k)^4+(x+h)^24][5x^4+x^24]}{h}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0which equetion we doing??

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3f(x) = \(5x^4 +x^2 4\) the limit way

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3except for it should say 5(x+h)^4 lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3the power rule is quicker, easier, and just as precise

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then do it in power rule ^^ if its that trustworthy

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3the power rule is the 'patter' that you discover after doing about a thousand limit ways

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it was Cx^n = C x nx^n1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then for 5(x+4)^4 its >>>> 5 x 4(x)^3 ???

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3ok.... you trying to use the x+h in that?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no i tried to use power rule that i did C.nx^n1

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.35x^4 ; try it on that one ...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3true; now put it all together; 20x^3

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3you did; the power rule takes a complicated form and reduces it to simple math

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes its really usefull :) to you, am i good at maths?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3you can be good at maths if you wanna be :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0:) really want to be ^^ i want to learn highschool units before i go to hichschool ^^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0really thanks amistre :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3youre welcome :) keep up the practics

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0normally just searching questions on Hz. google xd

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.3some good free practice can be had at interactmath.com
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