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this is what i get and it's wrong:
\[x= {2cx+2d \over a+b}\]
what am i doing wrong??!??

cause its lol

you still have x's on both sides

you didnt completly isolate the x

oh. wtf. i'm retarded

2(cx +d)= ax+b
2cx +2d = ax +b
get Xs into the same side and solve

x(2c-a) = b-2d

x = (b-2d)/(2c-a)

i missed the first step...?

subtract ax from both side

x(2c-a)=b-2a

i'm getting the same thing as you now. the book shows the answer as:
\[x= {2d - b \over a - 2c}\]

you factor out x in 5th line in my above post.

I made a mistake
x(2c-a)=b-2d

got it basketmath? or need an explanation?

i'm just following along. i am trying to take all this in. thanks for your guys help!

2d-b is the same as b-2d? That's where i am confused...

yeah, that's good.. always good to go in detail & understand every single bit :)