anonymous
  • anonymous
If 7,500 bacteria, with a growth constant k=0.4, are present 3hrs after beginning the experiment, how many are present 8 hrs later? a) 24,849 bacteria b) 2,259 bacteria c) 610,500 bacteria d) 184,000 bacteria
Mathematics
jamiebookeater
  • jamiebookeater
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amistre64
  • amistre64
i assume the k refers to 'percentage'
amistre64
  • amistre64
7500 = P(1.4)^3
amistre64
  • amistre64
P= 7500/(1.4)^3 X = [7500/(1.4)^3](1.4)^11

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amistre64
  • amistre64
the closest number i get to the choices is d, but i cant say for sure that I was right
amistre64
  • amistre64
i see it; e^kt ....
amistre64
  • amistre64
7500 = P.e^(.4*3)
amistre64
  • amistre64
183 ....... so its still D but with more confidence lol
anonymous
  • anonymous
okay thank you

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