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katykitz

  • 3 years ago

pls help.. the value of x when 2^(3x + 3) = 2^(3x + 1) + 48 is true a. 1 b. 3/2

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  1. shankvee\
    • 3 years ago
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    2^(3x+3)-64=2^(3x+1)-16 so now assume the equation is true for both LHS = RHS =0 2^(3x+3)=64 x=1; 2^(3x+1)=16 x=1; so the answer will be x=1;

  2. katykitz
    • 3 years ago
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    how did u get 64 & 16??pls tell me...

  3. shankvee\
    • 3 years ago
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    just by randomly looking at the problem.. i'm sorry i cant come up with anything definite 2^6=64 and 2^4=16 and 64-16=48 so.. You could just substitute and arrive at the answer easily...

  4. katykitz
    • 3 years ago
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    okie...tnx :)

  5. Aish
    • 3 years ago
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    assume the equation is true for both LHS = RHS =0 LHS: 2^(3x+3)=64 2^(3x+3)= 2^6 implies 3x+3=6 (since base is equal) equating 3x+3=6, we get x=1 similarly try for RHS and give me the answer

  6. katykitz
    • 3 years ago
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    k...got it ..thank u..:)

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