A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
write as logarithm of a single quantity: 1/3[4log5(x+1)3log5(3x)+6log5x]
anonymous
 4 years ago
write as logarithm of a single quantity: 1/3[4log5(x+1)3log5(3x)+6log5x]

This Question is Closed

nowhereman
 4 years ago
Best ResponseYou've already chosen the best response.0So how far do you get?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0not at all because its so confusing

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0actually it doesnt matter so lets just write log

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and ignore the 1/3 out front we will deal with it last

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0first use \[\log(a^n)=n\log(a)\] backwards. all the multipliers come inside the log as exponents

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[4\log(x+1)=\log((x+1)^4)\] \[3\log(3x)=\log((3x)^3)\] \[6\log(x)=\log(x^6)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0giving \[\log((x+1)^4)\log((3x)^3)+\log(x^6)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0now we use \[\log(a)log(b)=log(\frac{a}{b})\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what happened to the 1/3 outside the []

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i will deal with that last

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[log((x+1)^4)\log((3x)^3)=\log(\frac{(x+1)^4}{(3x)^3})\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0now we use \[\log(a)+\log(b)=\log(ab)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\log(\frac{(x+1)^4}{(3x)^3})+\log(x^6)=\log(\frac{x^6(x+1)^4}{(3x)^3})\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0now for the 1/3 out front. take the cube root of all that stuff.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the inner stuff i mean. the cube root of x^6 is x^2, and the cube root of (3x)^3 is 3x and so you get \[\log(\frac{x^2(x+1)^{\frac{4}{3}}}{3x})\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wow that was a hard problem but thanks again:)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.