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anonymous
 5 years ago
write as logarithm of a single quantity: 1/3[4log5(x+1)3log5(3x)+6log5x]
anonymous
 5 years ago
write as logarithm of a single quantity: 1/3[4log5(x+1)3log5(3x)+6log5x]

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nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0So how far do you get?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0not at all because its so confusing

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0actually it doesnt matter so lets just write log

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and ignore the 1/3 out front we will deal with it last

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0first use \[\log(a^n)=n\log(a)\] backwards. all the multipliers come inside the log as exponents

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[4\log(x+1)=\log((x+1)^4)\] \[3\log(3x)=\log((3x)^3)\] \[6\log(x)=\log(x^6)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0giving \[\log((x+1)^4)\log((3x)^3)+\log(x^6)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now we use \[\log(a)log(b)=log(\frac{a}{b})\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what happened to the 1/3 outside the []

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i will deal with that last

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[log((x+1)^4)\log((3x)^3)=\log(\frac{(x+1)^4}{(3x)^3})\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now we use \[\log(a)+\log(b)=\log(ab)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\log(\frac{(x+1)^4}{(3x)^3})+\log(x^6)=\log(\frac{x^6(x+1)^4}{(3x)^3})\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now for the 1/3 out front. take the cube root of all that stuff.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the inner stuff i mean. the cube root of x^6 is x^2, and the cube root of (3x)^3 is 3x and so you get \[\log(\frac{x^2(x+1)^{\frac{4}{3}}}{3x})\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wow that was a hard problem but thanks again:)
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