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animalsavior94
 4 years ago
write as logarithm of a single quantity: 1/3[4log5(x+1)3log5(3x)+6log5x]
animalsavior94
 4 years ago
write as logarithm of a single quantity: 1/3[4log5(x+1)3log5(3x)+6log5x]

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nowhereman
 4 years ago
Best ResponseYou've already chosen the best response.0So how far do you get?

animalsavior94
 4 years ago
Best ResponseYou've already chosen the best response.0not at all because its so confusing

satellite73
 4 years ago
Best ResponseYou've already chosen the best response.1is this log base 5?

satellite73
 4 years ago
Best ResponseYou've already chosen the best response.1actually it doesnt matter so lets just write log

satellite73
 4 years ago
Best ResponseYou've already chosen the best response.1and ignore the 1/3 out front we will deal with it last

animalsavior94
 4 years ago
Best ResponseYou've already chosen the best response.0yes its a base 5

satellite73
 4 years ago
Best ResponseYou've already chosen the best response.1first use \[\log(a^n)=n\log(a)\] backwards. all the multipliers come inside the log as exponents

satellite73
 4 years ago
Best ResponseYou've already chosen the best response.1\[4\log(x+1)=\log((x+1)^4)\] \[3\log(3x)=\log((3x)^3)\] \[6\log(x)=\log(x^6)\]

satellite73
 4 years ago
Best ResponseYou've already chosen the best response.1giving \[\log((x+1)^4)\log((3x)^3)+\log(x^6)\]

satellite73
 4 years ago
Best ResponseYou've already chosen the best response.1now we use \[\log(a)log(b)=log(\frac{a}{b})\]

animalsavior94
 4 years ago
Best ResponseYou've already chosen the best response.0what happened to the 1/3 outside the []

satellite73
 4 years ago
Best ResponseYou've already chosen the best response.1i will deal with that last

satellite73
 4 years ago
Best ResponseYou've already chosen the best response.1\[log((x+1)^4)\log((3x)^3)=\log(\frac{(x+1)^4}{(3x)^3})\]

satellite73
 4 years ago
Best ResponseYou've already chosen the best response.1now we use \[\log(a)+\log(b)=\log(ab)\]

satellite73
 4 years ago
Best ResponseYou've already chosen the best response.1\[\log(\frac{(x+1)^4}{(3x)^3})+\log(x^6)=\log(\frac{x^6(x+1)^4}{(3x)^3})\]

satellite73
 4 years ago
Best ResponseYou've already chosen the best response.1now for the 1/3 out front. take the cube root of all that stuff.

satellite73
 4 years ago
Best ResponseYou've already chosen the best response.1the inner stuff i mean. the cube root of x^6 is x^2, and the cube root of (3x)^3 is 3x and so you get \[\log(\frac{x^2(x+1)^{\frac{4}{3}}}{3x})\]

animalsavior94
 4 years ago
Best ResponseYou've already chosen the best response.0wow that was a hard problem but thanks again:)
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