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ilikechocolate45
 4 years ago
Solve the following system of equations alebraically:
2x+3y=17
3x2y=0.5
x=
y=
ilikechocolate45
 4 years ago
Solve the following system of equations alebraically: 2x+3y=17 3x2y=0.5 x= y=

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animalsavior94
 4 years ago
Best ResponseYou've already chosen the best response.0ok well first u need to find one variable so u do 2x+3y=17 2x=(3y+17)/2 x=3/2 y +17/2 3x2y=.5 now u substitue so 3(3/2 y + 17/2) 2y=.5 4.5+25.52y=.5 212y=.5 2y=20.5 y=10.25

animalsavior94
 4 years ago
Best ResponseYou've already chosen the best response.0now you got y, you can find x so 2x+3y=17 2x+3(10.25)=17 2x+30.75)=17 2x=13.25 x=6.625
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