dabears900
Help!! I have no idea!



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dabears900
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animalsavior94
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whatd your question?

dabears900
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see attached ^^^

animalsavior94
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i just did and ummmm im not very sure about it sorry:(

dabears900
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no probs! I hope someone might

rsvitale
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the direction of the gradient is the direction of greatest increase

rsvitale
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so take (dF/dx,dF/dy) at the point (1,1) and that vector points in the direction of greatest increase

rsvitale
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the magnitude of that vector is the greatest rate of change

rsvitale
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do you know how to find the partial derivatives?

dabears900
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yes, sorry I'm doing work at the same time

dabears900
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fx= 2x +y
fy = x

dabears900
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?

amistre64
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those look good for the gradient stuff

rsvitale
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yep they are right, now evaluate the derivatives at the specified point and you have the gradient vector. Then you can find magnitude.

dabears900
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so eval at (1,1) fx=1 fy =1

dabears900
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don't I need a z point?

dabears900
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magnitude is \sqrt((a_1)^2 + (a_2)^2) so I use the 1,1 ?

dabears900
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so the magnitdue is sqrt(2) ?

chaguanas
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\[<1/\sqrt{2}, 1/\sqrt{2}>\]