anonymous
  • anonymous
Help!! I have no idea!
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
whatd your question?
anonymous
  • anonymous
see attached ^^^

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anonymous
  • anonymous
i just did and ummmm im not very sure about it sorry:(
anonymous
  • anonymous
no probs! I hope someone might
anonymous
  • anonymous
the direction of the gradient is the direction of greatest increase
anonymous
  • anonymous
so take (dF/dx,dF/dy) at the point (-1,1) and that vector points in the direction of greatest increase
anonymous
  • anonymous
the magnitude of that vector is the greatest rate of change
anonymous
  • anonymous
do you know how to find the partial derivatives?
anonymous
  • anonymous
yes, sorry I'm doing work at the same time
anonymous
  • anonymous
fx= 2x +y fy = x
anonymous
  • anonymous
?
amistre64
  • amistre64
those look good for the gradient stuff
anonymous
  • anonymous
yep they are right, now evaluate the derivatives at the specified point and you have the gradient vector. Then you can find magnitude.
anonymous
  • anonymous
so eval at (-1,1) fx=-1 fy =-1
anonymous
  • anonymous
don't I need a z point?
anonymous
  • anonymous
magnitude is \sqrt((a_1)^2 + (a_2)^2) so I use the -1,-1 ?
anonymous
  • anonymous
so the magnitdue is sqrt(2) ?
anonymous
  • anonymous
\[<-1/\sqrt{2}, 1/\sqrt{2}>\]

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