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Help!! I have no idea!

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whatd your question?
see attached ^^^

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Other answers:

i just did and ummmm im not very sure about it sorry:(
no probs! I hope someone might
the direction of the gradient is the direction of greatest increase
so take (dF/dx,dF/dy) at the point (-1,1) and that vector points in the direction of greatest increase
the magnitude of that vector is the greatest rate of change
do you know how to find the partial derivatives?
yes, sorry I'm doing work at the same time
fx= 2x +y fy = x
those look good for the gradient stuff
yep they are right, now evaluate the derivatives at the specified point and you have the gradient vector. Then you can find magnitude.
so eval at (-1,1) fx=-1 fy =-1
don't I need a z point?
magnitude is \sqrt((a_1)^2 + (a_2)^2) so I use the -1,-1 ?
so the magnitdue is sqrt(2) ?
\[<-1/\sqrt{2}, 1/\sqrt{2}>\]

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