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Q=kor*(0.5)^2*(0.9)^1/2 kor=2.09
Q=2.09*(0.5)^2*(0.9)^1/2
Q=0.49568...
Now say if I knew Q was 0.495.. and wanted to find kor, how would I rearrange the formula to get the answer 2.09?
0.4956=kor*(0.5)^2*(0.9)^1/2
Btw the above formula is related to Water Calcs for Orfices if it helps.
 2 years ago
 2 years ago
Q=kor*(0.5)^2*(0.9)^1/2 kor=2.09 Q=2.09*(0.5)^2*(0.9)^1/2 Q=0.49568... Now say if I knew Q was 0.495.. and wanted to find kor, how would I rearrange the formula to get the answer 2.09? 0.4956=kor*(0.5)^2*(0.9)^1/2 Btw the above formula is related to Water Calcs for Orfices if it helps.
 2 years ago
 2 years ago

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OwlfredBest ResponseYou've already chosen the best response.0
Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!
 2 years ago

AnnandBest ResponseYou've already chosen the best response.1
kor=Q/[(0.5)^2*(0.9)^0.5]
 2 years ago

lrain5Best ResponseYou've already chosen the best response.0
Yeah worked perfectly, having a brain freeze as I have a test in two days and stressing. Thanks alot!
 2 years ago
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