Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

madhu12

  • 4 years ago

how would we find the unit vector in the direction of v= i+j?

  • This Question is Closed
  1. Owlfred
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

  2. eseidl
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    The vector i=<1,0> and j=<0,1> so the i+j=<1+0,0+1>=<1,1>. The length of this vector is easy: |i+j|=\[\sqrt{2}\] to make the vector i+j=<1,1> a unit vector we rescale it by it's length (i.e. divide i+j by its length) , v=(i+j)/(|i+j|) thus we have v=\[1/\sqrt{2} <1,1>\] or \[<1/\sqrt{2}, 1/\sqrt{2}>\] If you check the length of this vector v, you see it indeed does have length =1. It is parallel to the vector i+j because it's components are proportional to the components of i+j=<1,1>.

  3. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy