A community for students. Sign up today

Here's the question you clicked on:

madhu12 4 years ago how would we find the unit vector in the direction of v= i+j?

• This Question is Closed
1. Owlfred

Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

2. eseidl

The vector i=<1,0> and j=<0,1> so the i+j=<1+0,0+1>=<1,1>. The length of this vector is easy: |i+j|=$\sqrt{2}$ to make the vector i+j=<1,1> a unit vector we rescale it by it's length (i.e. divide i+j by its length) , v=(i+j)/(|i+j|) thus we have v=$1/\sqrt{2} <1,1>$ or $<1/\sqrt{2}, 1/\sqrt{2}>$ If you check the length of this vector v, you see it indeed does have length =1. It is parallel to the vector i+j because it's components are proportional to the components of i+j=<1,1>.

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy