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Owlfred
 3 years ago
Best ResponseYou've already chosen the best response.1Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

eseidl
 3 years ago
Best ResponseYou've already chosen the best response.1The vector i=<1,0> and j=<0,1> so the i+j=<1+0,0+1>=<1,1>. The length of this vector is easy: i+j=\[\sqrt{2}\] to make the vector i+j=<1,1> a unit vector we rescale it by it's length (i.e. divide i+j by its length) , v=(i+j)/(i+j) thus we have v=\[1/\sqrt{2} <1,1>\] or \[<1/\sqrt{2}, 1/\sqrt{2}>\] If you check the length of this vector v, you see it indeed does have length =1. It is parallel to the vector i+j because it's components are proportional to the components of i+j=<1,1>.
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