anonymous
  • anonymous
graph each function; 1.h(X)=2|x|,where the domain is {-1,0,1,2} 2.f(X)=x-1, where the domain is {x|x is a real #]
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
1. hmmm. Im not sure what the domain brackets mean. is it set notation? usually wouldn't it just have two values? like: [-1,1] to show from -1 to 1 ? 2. again, im confused by the brackets. But ignoring that, it' should just be the same as y=x except that it is shifted down 1
anonymous
  • anonymous
All the first one does is make it thinner. So the "v" won't be as wide.
anonymous
  • anonymous
But I agree, the {}'s are confusing.

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