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(10,0)

oh, the equation, not the point lol

yeah haha could you please show the work? thank you

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r cos(t) =10
r = 10/cos(t)

where did u get t from?

well, x = r cos(t) thats just by definition

so, r cos(t) = 10 is a direct translation to polar form

do you mean theta?

i dont think I did the divide right tho

yes; t = theta ... it really doesnt matter what you call it, it never comes when called

ohh ok thanks i was just checking because i was confused. anyways so the answer is r=10/cos theta

maybe, i cant remember if the divide by 0 applies to mess things up with

im not sure either its quite confusing

how do you get secant?

r = sec and 1/cos are the same thing

\[sec = \frac{1}{cos}\]

\[\frac{10}{cos}=10 sec\]

i see thanks so much for your explanations

youre welcome :)

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