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what do you need help on?

whats your q?

4X^2(3X^2)(X)=

you can use:\[x ^{a}\times x ^{b} = x^{a+b}\]

you can break this down into \[4\times x ^{2}\times 3\times x^{2} \times x^1\]

i dont get this???

you can do the 4x3 easily and then use the equation the combine the x together

so you get 12 and then the exponents are 2, 2, 1

so think of 2, 2, 1 as a, b, c

Then \[x^{2}\times x^{2} \times x^{1} \]
which is
\[x^{a}\times x^{b} \times x^{c} = x^{2+2+1}\]

combine the 12 you got from 4 and 3 you get \[12\times x^{5} \] which is your answer