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davette

  • 4 years ago

hELP

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  1. kanade
    • 4 years ago
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    what do you need help on?

  2. animalsavior94
    • 4 years ago
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    whats your q?

  3. davette
    • 4 years ago
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    4X^2(3X^2)(X)=

  4. kanade
    • 4 years ago
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    you can use:\[x ^{a}\times x ^{b} = x^{a+b}\]

  5. kanade
    • 4 years ago
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    you can break this down into \[4\times x ^{2}\times 3\times x^{2} \times x^1\]

  6. davette
    • 4 years ago
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    i dont get this???

  7. kanade
    • 4 years ago
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    you can do the 4x3 easily and then use the equation the combine the x together

  8. kanade
    • 4 years ago
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    so you get 12 and then the exponents are 2, 2, 1

  9. kanade
    • 4 years ago
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    so think of 2, 2, 1 as a, b, c

  10. kanade
    • 4 years ago
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    Then \[x^{2}\times x^{2} \times x^{1} \] which is \[x^{a}\times x^{b} \times x^{c} = x^{2+2+1}\]

  11. kanade
    • 4 years ago
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    combine the 12 you got from 4 and 3 you get \[12\times x^{5} \] which is your answer

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