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## davette Group Title hELP 3 years ago 3 years ago

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1. kanade

what do you need help on?

2. animalsavior94

whats your q?

3. davette

4X^2(3X^2)(X)=

4. kanade

you can use:$x ^{a}\times x ^{b} = x^{a+b}$

5. kanade

you can break this down into $4\times x ^{2}\times 3\times x^{2} \times x^1$

6. davette

i dont get this???

7. kanade

you can do the 4x3 easily and then use the equation the combine the x together

8. kanade

so you get 12 and then the exponents are 2, 2, 1

9. kanade

so think of 2, 2, 1 as a, b, c

10. kanade

Then $x^{2}\times x^{2} \times x^{1}$ which is $x^{a}\times x^{b} \times x^{c} = x^{2+2+1}$

11. kanade

combine the 12 you got from 4 and 3 you get $12\times x^{5}$ which is your answer