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what do you need help on?
whats your q?
4X^2(3X^2)(X)=

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Other answers:

you can use:\[x ^{a}\times x ^{b} = x^{a+b}\]
you can break this down into \[4\times x ^{2}\times 3\times x^{2} \times x^1\]
i dont get this???
you can do the 4x3 easily and then use the equation the combine the x together
so you get 12 and then the exponents are 2, 2, 1
so think of 2, 2, 1 as a, b, c
Then \[x^{2}\times x^{2} \times x^{1} \] which is \[x^{a}\times x^{b} \times x^{c} = x^{2+2+1}\]
combine the 12 you got from 4 and 3 you get \[12\times x^{5} \] which is your answer

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