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kanadeBest ResponseYou've already chosen the best response.1
what do you need help on?
 2 years ago

kanadeBest ResponseYou've already chosen the best response.1
you can use:\[x ^{a}\times x ^{b} = x^{a+b}\]
 2 years ago

kanadeBest ResponseYou've already chosen the best response.1
you can break this down into \[4\times x ^{2}\times 3\times x^{2} \times x^1\]
 2 years ago

kanadeBest ResponseYou've already chosen the best response.1
you can do the 4x3 easily and then use the equation the combine the x together
 2 years ago

kanadeBest ResponseYou've already chosen the best response.1
so you get 12 and then the exponents are 2, 2, 1
 2 years ago

kanadeBest ResponseYou've already chosen the best response.1
so think of 2, 2, 1 as a, b, c
 2 years ago

kanadeBest ResponseYou've already chosen the best response.1
Then \[x^{2}\times x^{2} \times x^{1} \] which is \[x^{a}\times x^{b} \times x^{c} = x^{2+2+1}\]
 2 years ago

kanadeBest ResponseYou've already chosen the best response.1
combine the 12 you got from 4 and 3 you get \[12\times x^{5} \] which is your answer
 2 years ago
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