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can someone please explain to me how the derivative of f(x)=sin x is?? and how its found.
 2 years ago
 2 years ago
can someone please explain to me how the derivative of f(x)=sin x is?? and how its found.
 2 years ago
 2 years ago

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amistre64Best ResponseYou've already chosen the best response.0
lim as h> 0; sin(x+h)sin(x)  h
 2 years ago

MITL3ARN3RBest ResponseYou've already chosen the best response.0
so, theres no cosine involved in the answer.
 2 years ago

amistre64Best ResponseYou've already chosen the best response.0
sin(x+h) = sin(x)cos(h) + sin(h)cos(x) sin(x)cos(h) + sin(h)cos(x)  sin(x) = sin(x)(cos(h)1) + sin(h)cos(x)
 2 years ago

amistre64Best ResponseYou've already chosen the best response.0
\[sin(x)\frac{cos(h)1}{h}+cos(x)\frac{sin(h)}{h}\]
 2 years ago

amistre64Best ResponseYou've already chosen the best response.0
\[\frac{cos(h)1}{h} \implies 0;\ and \frac{sin(h)}{h} \implies 1\]
 2 years ago

amistre64Best ResponseYou've already chosen the best response.0
0 + cos(x) = cos(x) Dx(sin(x)) = cos(x)
 2 years ago

AnnandBest ResponseYou've already chosen the best response.2
\[d(\sin x)/dx=\lim_{dx \rightarrow 0} [\sin(x+dx) \sin(x)]/[x+dxx]\] \[d(\sin x)/dx=\lim_{dx \rightarrow 0} [2\cos(x+dx/2)*\sin(dx/2)]/[dx]\] \[= \lim_{dx \rightarrow 0} [\cos(x+dx/2)]*\ [\sin(dx/2)]/[dx/2]\] =cos(x)
 2 years ago

MITL3ARN3RBest ResponseYou've already chosen the best response.0
in the change of delta x, why is h by itself , what were the other two variables that were cancelled out
 2 years ago

MITL3ARN3RBest ResponseYou've already chosen the best response.0
go for it bro dont be shamed
 2 years ago

AnnandBest ResponseYou've already chosen the best response.2
\[\lim_{a \rightarrow 0} \sin(a)/a=1\]
 2 years ago

MITL3ARN3RBest ResponseYou've already chosen the best response.0
i just cant understand it how sin x ends up cos x , the derivative of the function,
 2 years ago

AnnandBest ResponseYou've already chosen the best response.2
sin(A)sin(B)=2*cos((A+B)/2)*sin((AB)/2)
 2 years ago

AnnandBest ResponseYou've already chosen the best response.2
hope you know the general eqn for finding derivatives...
 2 years ago

MITL3ARN3RBest ResponseYou've already chosen the best response.0
no , LOL, ill get it though thats a promise
 2 years ago
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