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bendtBest ResponseYou've already chosen the best response.1
\[ax^2+bx+c=0\implies x=\frac{b\pm \sqrt{b^24ac}}{2a}\]Work it out for yourself.
 2 years ago

AnnandBest ResponseYou've already chosen the best response.1
just substitute a,b and c into the eqn provided by bendt... here a=2 b=9 c=4
 2 years ago

radarBest ResponseYou've already chosen the best response.0
and verify the results by factoring.
 2 years ago

Abbie23Best ResponseYou've already chosen the best response.0
Aww thanks you're awesome:)
 2 years ago

AnnandBest ResponseYou've already chosen the best response.1
That was another method of finding the roots... Sorry, i deleted it thinking it might confuse you...
 2 years ago

Abbie23Best ResponseYou've already chosen the best response.0
It's okay you still tried to help so that's all that matters:)
 2 years ago
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