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\[ax^2+bx+c=0\implies x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\]Work it out for yourself.

just substitute a,b and c into the eqn provided by bendt...
here
a=2
b=9
c=4

and verify the results by factoring.

Aww thanks you're awesome:)

That was another method of finding the roots...
Sorry, i deleted it thinking it might confuse you...

It's okay you still tried to help so that's all that matters:)