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loco85
 3 years ago
The displacement (in meters) of a particle moving in a straight line is given by the equation of motion below, where t is measured in seconds.
http://www.webassign.net/cgibin/symimage.cgi?expr=s%20%3D%207%2Ft%5E2
(a) Find the velocity of the particle at time t = a.
m/s
(b) Find the velocity of the particle at time t = 1.
m/s
(c) Find the velocity of the particle at time t = 2.
m/s
(d) Find the velocity of the particle at time t = 3.
m/s
loco85
 3 years ago
The displacement (in meters) of a particle moving in a straight line is given by the equation of motion below, where t is measured in seconds. http://www.webassign.net/cgibin/symimage.cgi?expr=s%20%3D%207%2Ft%5E2 (a) Find the velocity of the particle at time t = a. m/s (b) Find the velocity of the particle at time t = 1. m/s (c) Find the velocity of the particle at time t = 2. m/s (d) Find the velocity of the particle at time t = 3. m/s

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bendt
 3 years ago
Best ResponseYou've already chosen the best response.1Differentiate and put your values of t in.

dhatraditya
 3 years ago
Best ResponseYou've already chosen the best response.0velocity is ds/dt so differentiate your equation, then plug in values for t

loco85
 3 years ago
Best ResponseYou've already chosen the best response.0It's not multiple choice.

dhatraditya
 3 years ago
Best ResponseYou've already chosen the best response.0huh? this is not a multiple choice question

loco85
 3 years ago
Best ResponseYou've already chosen the best response.0I'm having trouble figuring out how to do it.

alice_smith
 3 years ago
Best ResponseYou've already chosen the best response.0u get better i tryed

bendt
 3 years ago
Best ResponseYou've already chosen the best response.1\[v=\frac{ds}{dt}=\frac{d(7t^{2})}{dt}=14t^{3}\]That's your function for velocity, now just plug in the values of t.

loco85
 3 years ago
Best ResponseYou've already chosen the best response.0What would the value for a be then?

loco85
 3 years ago
Best ResponseYou've already chosen the best response.0The way you showed is really helpful.
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