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ScRyX
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x = + 5

Chandman
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lol lx+12l =8

Chandman
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I dont know how to do the absolute value symbols, so bear with me

ScRyX
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x+12 = 8 is the same as  x (12) = 8, therefore x is either 20 or 4.

ScRyX
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simply, a  b is the distance between a and b on the real axis.

Chandman
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6x=10
I know one of them is 4 but whats the other T_T

anonymous
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\[x+12=8\] solve two equations
\[x+12=8\] or
\[x+12=8\] first one gives
\[x=4\]
second one gives
\[x=20\]

Chandman
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lol fail. I forgot that was a negative

Chandman
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lxl3=6

anonymous
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\[6x=10\] same as
\[x6=10\]
solve
\[x6=10\] or
\[x6=10\]

anonymous
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convince yourself that
\[ab=ba\] so you do not have to deal with the annoying
\[6x\] just change to
\[x6\]

Chandman
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whered you get the 10?

anonymous
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you wrote
\[6x=10\] i just changed it to
\[x6=10\]

Chandman
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lol.
Thought we were working on this one D:
lxl3=6

anonymous
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this one is easier. this one is
\[x=9\]
making
\[x=\pm 9\]

Chandman
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okay for lx+4l=3 you would make it 4+x=3 and 4=x=3, correct?

Chandman
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that last part was supposed to say 4+x=3