## Chandman 4 years ago lxl-2=3

1. ScRyX

x = +- 5

2. Chandman

lol lx+12l =8

3. Chandman

I dont know how to do the absolute value symbols, so bear with me

4. ScRyX

|x+12| = 8 is the same as | x -(-12)| = 8, therefore x is either -20 or -4.

5. ScRyX

simply, |a - b| is the distance between a and b on the real axis.

6. Chandman

|6-x|=10 I know one of them is 4 but whats the other T_T

7. satellite73

$|x+12|=8$ solve two equations $x+12=8$ or $x+12=-8$ first one gives $x=-4$ second one gives $x=-20$

8. Chandman

lol fail. I forgot that was a negative

9. Chandman

lxl-3=6

10. satellite73

$|6-x|=10$ same as $|x-6|=10$ solve $x-6=10$ or $x-6=-10$

11. satellite73

convince yourself that $|a-b|=|b-a|$ so you do not have to deal with the annoying $|6-x|$ just change to $|x-6|$

12. Chandman

whered you get the 10?

13. satellite73

you wrote $|6-x|=10$ i just changed it to $|x-6|=10$

14. Chandman

lol. Thought we were working on this one D: lxl-3=6

15. satellite73

this one is easier. this one is $|x|=9$ making $x=\pm 9$

16. Chandman

okay for lx+4l=3 you would make it 4+x=-3 and 4=x=3, correct?

17. Chandman

that last part was supposed to say 4+x=3