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x = +- 5

lol lx+12l =8

I dont know how to do the absolute value symbols, so bear with me

|x+12| = 8 is the same as | x -(-12)| = 8, therefore x is either -20 or -4.

simply, |a - b| is the distance between a and b on the real axis.

|6-x|=10
I know one of them is 4 but whats the other T_T

lol fail. I forgot that was a negative

lxl-3=6

\[|6-x|=10\] same as
\[|x-6|=10\]
solve
\[x-6=10\] or
\[x-6=-10\]

whered you get the 10?

you wrote
\[|6-x|=10\] i just changed it to
\[|x-6|=10\]

lol.
Thought we were working on this one D:
lxl-3=6

this one is easier. this one is
\[|x|=9\]
making
\[x=\pm 9\]

okay for lx+4l=3 you would make it 4+x=-3 and 4=x=3, correct?

that last part was supposed to say 4+x=3