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Chandman

lxl-2=3

  • 2 years ago
  • 2 years ago

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  1. ScRyX
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    x = +- 5

    • 2 years ago
  2. Chandman
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    lol lx+12l =8

    • 2 years ago
  3. Chandman
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    I dont know how to do the absolute value symbols, so bear with me

    • 2 years ago
  4. ScRyX
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    |x+12| = 8 is the same as | x -(-12)| = 8, therefore x is either -20 or -4.

    • 2 years ago
  5. ScRyX
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    simply, |a - b| is the distance between a and b on the real axis.

    • 2 years ago
  6. Chandman
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    |6-x|=10 I know one of them is 4 but whats the other T_T

    • 2 years ago
  7. satellite73
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    \[|x+12|=8\] solve two equations \[x+12=8\] or \[x+12=-8\] first one gives \[x=-4\] second one gives \[x=-20\]

    • 2 years ago
  8. Chandman
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    lol fail. I forgot that was a negative

    • 2 years ago
  9. Chandman
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    lxl-3=6

    • 2 years ago
  10. satellite73
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    \[|6-x|=10\] same as \[|x-6|=10\] solve \[x-6=10\] or \[x-6=-10\]

    • 2 years ago
  11. satellite73
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    convince yourself that \[|a-b|=|b-a|\] so you do not have to deal with the annoying \[|6-x|\] just change to \[|x-6|\]

    • 2 years ago
  12. Chandman
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    whered you get the 10?

    • 2 years ago
  13. satellite73
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    you wrote \[|6-x|=10\] i just changed it to \[|x-6|=10\]

    • 2 years ago
  14. Chandman
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    lol. Thought we were working on this one D: lxl-3=6

    • 2 years ago
  15. satellite73
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    this one is easier. this one is \[|x|=9\] making \[x=\pm 9\]

    • 2 years ago
  16. Chandman
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    okay for lx+4l=3 you would make it 4+x=-3 and 4=x=3, correct?

    • 2 years ago
  17. Chandman
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    that last part was supposed to say 4+x=3

    • 2 years ago
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