anonymous
  • anonymous
lxl-2=3
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
x = +- 5
anonymous
  • anonymous
lol lx+12l =8
anonymous
  • anonymous
I dont know how to do the absolute value symbols, so bear with me

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anonymous
  • anonymous
|x+12| = 8 is the same as | x -(-12)| = 8, therefore x is either -20 or -4.
anonymous
  • anonymous
simply, |a - b| is the distance between a and b on the real axis.
anonymous
  • anonymous
|6-x|=10 I know one of them is 4 but whats the other T_T
anonymous
  • anonymous
\[|x+12|=8\] solve two equations \[x+12=8\] or \[x+12=-8\] first one gives \[x=-4\] second one gives \[x=-20\]
anonymous
  • anonymous
lol fail. I forgot that was a negative
anonymous
  • anonymous
lxl-3=6
anonymous
  • anonymous
\[|6-x|=10\] same as \[|x-6|=10\] solve \[x-6=10\] or \[x-6=-10\]
anonymous
  • anonymous
convince yourself that \[|a-b|=|b-a|\] so you do not have to deal with the annoying \[|6-x|\] just change to \[|x-6|\]
anonymous
  • anonymous
whered you get the 10?
anonymous
  • anonymous
you wrote \[|6-x|=10\] i just changed it to \[|x-6|=10\]
anonymous
  • anonymous
lol. Thought we were working on this one D: lxl-3=6
anonymous
  • anonymous
this one is easier. this one is \[|x|=9\] making \[x=\pm 9\]
anonymous
  • anonymous
okay for lx+4l=3 you would make it 4+x=-3 and 4=x=3, correct?
anonymous
  • anonymous
that last part was supposed to say 4+x=3

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