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sierra14

  • 4 years ago

determine the vertex and the axis of symmetry for the function Y=-x^2+2x+1

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  1. sierra14
    • 4 years ago
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    \[Y=-x^2+2x+1\]

  2. Chandman
    • 4 years ago
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    Can Somebody help me please D:

  3. anonymous
    • 4 years ago
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    same magic formula as before. use \[\frac{-b}{2a}\] for the first coordinate of the vertex. second coordinate is what you get when you plug it in

  4. anonymous
    • 4 years ago
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    in this case a = -1, b = 2 so \[-\frac{b}{2a}=-\frac{2}{2\times(-1)}=1\]

  5. anonymous
    • 4 years ago
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    plug in 1 for x and you win. i get -1+2+1=2 so vertex is (1,2)

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