A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
why isnt anyone helping me?!
anonymous
 4 years ago
why isnt anyone helping me?!

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0could you please explain the different laws or stuff you could do in logs? because i am so confused about the entire chapter logs and i got a final exam tomorrow so im stressing out

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Okay. :) A logarithm is the inverse of an exponential in the same sense the square root (almost) is the inverse of squaring something. So if you have something like: log(7x)=2 You can raise both sides by 10 so: 10^(log(7x))=10^2 Giving: 7x=100 However, the same works in reverse. Given 10^7x=10^2 You can take the log log(10^7x)=log(10^2) 7x=2 One nice thing about logarithms is the "base" in which if you have 2^x you can take log base TWO to simplify it to x. There are several properties of logs. \[\log(ab)=\log(a)+\log(b)\] \[\log(\frac{a}{b})=\log(a)\log(b)\] \[\log_a(x)=\frac{\log_b(x)}{\log_b(a)}\](change of base) \[\log_a(a^x)=x\] NOTE: If I have log it is assumed base 10. Ln is assumed log base e (e=2.718...) Also, a more obscure manipulation is: \[\log_a(x)=\log_\frac{1}{a}(x)\] You can rewrite logs bringing powers down as coefficients. \[\log_a(x^n)=nlog_a(x)\] NOTE: if you have:\[\log_a^n(x)\neq nlog_a(x)\] Make sure you realize the difference. Any questions?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Forgot one: \[a^{\log_a(x)}=x\] (same as one of the above but in reverse)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0im so screwed for the exam:(

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well I can help you work through examples if you want. That's about all I know about logs except stuff involving calculus and stuff xP

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well the exam im taking tomorrow bright and early at 9am tomorrow is pre calc. I never understood logs ever since algebra 2 lol its really confusing especially the change base and stuff aka exponential form

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well find some questions you don't understand and I'll try to explain if you want :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0aww you would do that to help me? thanks sooo much! i appreciate it greatly!!:D

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0No problem :) I should be on for about an hr and a half. Then I'll be off for about 20 then I'll be back for another hour or so :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that sounds pretty good! thank you soooo much once again!!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0No problem :) Just post whatever you get stuck on.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[1/2\ln x+\ln (x+3)\ln (x ^{2}+1)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0condense it to a log of a single quantity

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'm assuming you want to combine it. Using properties you can see that: \[\frac{1}{2}\ln(x)=\ln(x^{\frac{1}{2}})\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0From here you have an addition of two logs, then a subtraction of another. This means the two additions will be in the numerator of the new combined log, and the subtracted one will be in the denominator. So: \[\ln(x^{1/2})+\ln(x+3)=\ln(x^{1/2}(x+3))\] Then from here you have: \[\ln(x^{1/2}(x+3))\ln(x^2+1)=\ln(\frac{x^{1/2}(x+3)}{x^2+1})\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.