animalsavior94
why doesnt x^38=(x2)^3??? please reply!



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amistre64
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becasue they are 2 different operations

amistre64
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exponents are(nt) distributive across addition

malevolence19
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In one you are cubing the x and subtracting the 8. In the other you are subtracting the 2 then cubing it.
On a side not: I WANNA BE A MOD AMISTRE!!!

Cutiepo0
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because (x2)^3 is like (x2)(x2)(x2)

Cutiepo0
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so, it doesn't equal the same as x^38

malevolence19
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AMISTRE!!! D: My lip is poking out :(

PeerEducator
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Multiply out \[(x2)^3\] and you will see that the answer is not \[x^38\]

malevolence19
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In general:
\[(a+b)^n \neq a^n+b^n\]

animalsavior94
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but how would u know it is (x2)(x^2+2x+4)

malevolence19
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We agree that 2^3=2*2*2?
So:
(x2)^3=(x2)(x2)(x2)
So you can get:
(x2)(x^2+2x+4)

animalsavior94
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ohhh i understand thanks so muh guys!