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amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0becasue they are 2 different operations

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0exponents are(nt) distributive across addition

malevolence19
 3 years ago
Best ResponseYou've already chosen the best response.1In one you are cubing the x and subtracting the 8. In the other you are subtracting the 2 then cubing it. On a side not: I WANNA BE A MOD AMISTRE!!!

Cutiepo0
 3 years ago
Best ResponseYou've already chosen the best response.3because (x2)^3 is like (x2)(x2)(x2)

Cutiepo0
 3 years ago
Best ResponseYou've already chosen the best response.3so, it doesn't equal the same as x^38

malevolence19
 3 years ago
Best ResponseYou've already chosen the best response.1AMISTRE!!! D: My lip is poking out :(

PeerEducator
 3 years ago
Best ResponseYou've already chosen the best response.0Multiply out \[(x2)^3\] and you will see that the answer is not \[x^38\]

malevolence19
 3 years ago
Best ResponseYou've already chosen the best response.1In general: \[(a+b)^n \neq a^n+b^n\]

animalsavior94
 3 years ago
Best ResponseYou've already chosen the best response.0but how would u know it is (x2)(x^2+2x+4)

malevolence19
 3 years ago
Best ResponseYou've already chosen the best response.1We agree that 2^3=2*2*2? So: (x2)^3=(x2)(x2)(x2) So you can get: (x2)(x^2+2x+4)

animalsavior94
 3 years ago
Best ResponseYou've already chosen the best response.0ohhh i understand thanks so muh guys!
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