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animalsavior94

  • 3 years ago

why doesnt x^3-8=(x-2)^3??? please reply!

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  1. amistre64
    • 3 years ago
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    becasue they are 2 different operations

  2. amistre64
    • 3 years ago
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    exponents are(nt) distributive across addition

  3. malevolence19
    • 3 years ago
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    In one you are cubing the x and subtracting the 8. In the other you are subtracting the 2 then cubing it. On a side not: I WANNA BE A MOD AMISTRE!!!

  4. Cutiepo0
    • 3 years ago
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    because (x-2)^3 is like (x-2)(x-2)(x-2)

  5. Cutiepo0
    • 3 years ago
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    so, it doesn't equal the same as x^3-8

  6. malevolence19
    • 3 years ago
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    AMISTRE!!! D: My lip is poking out :(

  7. PeerEducator
    • 3 years ago
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    Multiply out \[(x-2)^3\] and you will see that the answer is not \[x^3-8\]

  8. malevolence19
    • 3 years ago
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    In general: \[(a+b)^n \neq a^n+b^n\]

  9. animalsavior94
    • 3 years ago
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    but how would u know it is (x-2)(x^2+2x+4)

  10. malevolence19
    • 3 years ago
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    We agree that 2^3=2*2*2? So: (x-2)^3=(x-2)(x-2)(x-2) So you can get: (x-2)(x^2+2x+4)

  11. animalsavior94
    • 3 years ago
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    ohhh i understand thanks so muh guys!

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