anonymous
  • anonymous
why doesnt x^3-8=(x-2)^3??? please reply!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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amistre64
  • amistre64
becasue they are 2 different operations
amistre64
  • amistre64
exponents are(nt) distributive across addition
anonymous
  • anonymous
In one you are cubing the x and subtracting the 8. In the other you are subtracting the 2 then cubing it. On a side not: I WANNA BE A MOD AMISTRE!!!

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anonymous
  • anonymous
because (x-2)^3 is like (x-2)(x-2)(x-2)
anonymous
  • anonymous
so, it doesn't equal the same as x^3-8
anonymous
  • anonymous
AMISTRE!!! D: My lip is poking out :(
anonymous
  • anonymous
Multiply out \[(x-2)^3\] and you will see that the answer is not \[x^3-8\]
anonymous
  • anonymous
In general: \[(a+b)^n \neq a^n+b^n\]
anonymous
  • anonymous
but how would u know it is (x-2)(x^2+2x+4)
anonymous
  • anonymous
We agree that 2^3=2*2*2? So: (x-2)^3=(x-2)(x-2)(x-2) So you can get: (x-2)(x^2+2x+4)
anonymous
  • anonymous
ohhh i understand thanks so muh guys!

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