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anonymous
 5 years ago
why doesnt x^38=(x2)^3??? please reply!
anonymous
 5 years ago
why doesnt x^38=(x2)^3??? please reply!

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0becasue they are 2 different operations

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0exponents are(nt) distributive across addition

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0In one you are cubing the x and subtracting the 8. In the other you are subtracting the 2 then cubing it. On a side not: I WANNA BE A MOD AMISTRE!!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0because (x2)^3 is like (x2)(x2)(x2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so, it doesn't equal the same as x^38

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0AMISTRE!!! D: My lip is poking out :(

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Multiply out \[(x2)^3\] and you will see that the answer is not \[x^38\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0In general: \[(a+b)^n \neq a^n+b^n\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but how would u know it is (x2)(x^2+2x+4)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0We agree that 2^3=2*2*2? So: (x2)^3=(x2)(x2)(x2) So you can get: (x2)(x^2+2x+4)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohhh i understand thanks so muh guys!
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