X+y = 2
find the interger solutions of the equation.
Stacey Warren - Expert brainly.com
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is it 2xy-z^2=0??
oh wait , forgot to type it out, no, 2xy-z^2=1
if it is so ..then
so plot the sphere with radius sqrt(3) and find the points which has integer (x,y,z) triplet
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one such point is (1,1,1)
only this is the solution..no other points are there.
u can prove it by this way
sqrt(xy)<=1 as x+y=2
z=1 only integer..
s0 x=1 y=1 the solution..
(1,1,1) is the only possible solutin
actually I have the solution to the question which is x+y=2 and 2xy-z^2=1 leads to 2(x-1)^2+z^2=1, hence interger solutions are (1,1,1) and (1,1,-1) but i dont really get it, preparing for a math test which im not par with.
ok....take my equation x^2+y^2+z^2=3
so it can be x^2=1, y^2=1, z^2=1
now x+y=2>0 so x,y>0
but z^2=1 gives z=1,-1
so (1,1,1) and (1,1-1)
i get that z can be either -1 ,1 but how did you get x^2+y^2+z^2=3?
and also from second approach z^2<=1
and both x,y>0