Find the smallest interger such that if dividied by 2 leaves a remainder of 1 , if divided by 3 leaves a remainder of 2, if divided by 4 leaves a remainder of 3 and if divided by 5 leaves a remainder of 4
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Instinctively look for an odd prime as there is a remainder when divided by odd or even numbers.
So choose the smallest prime greater than the greates divisor, in this case 7 and continue.
Not 5 as divised by 3 leaves a remainder of 1 not 2.
Now try 11
Not 11 as leaves remainder 1 when divided by 5
The answer is 59
This method is called trial and improvement but there is a better way using modulus mathematics.
this number must be of the form 5n + 4 where n is odd eg 29, 39, 49 - it must also end in 9.
59 - yep 59