Here's the question you clicked on:
nuox95
simplify [1+n(n+1)(n+2)(n+3)]^(1/2)
[1+(n^2+n)(n+2)(n+3)]^(1/2)= [1+(n^2+n)(n^2+3n+2n+6)]^(1/2)= [1+(n^2+n)(n^2+5n+6)]^(1/2)
=[1+(n^4+5n^3+6n^2+n^3+5n^2+6n)]^(1/2)
=[1+(n^4+6n^3+11n^2+6n)]^(1/2), that's as far as you can simplify..
lets try this \[1+n(n+1)(n+2)(n+3)=(n(n+3)+1)^2\] and thefore your answer is \[n(n+3)+1\]