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nuox95

  • 4 years ago

simplify [1+n(n+1)(n+2)(n+3)]^(1/2)

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  1. bahrom7893
    • 4 years ago
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    [1+(n^2+n)(n+2)(n+3)]^(1/2)= [1+(n^2+n)(n^2+3n+2n+6)]^(1/2)= [1+(n^2+n)(n^2+5n+6)]^(1/2)

  2. bahrom7893
    • 4 years ago
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    =[1+(n^4+5n^3+6n^2+n^3+5n^2+6n)]^(1/2)

  3. bahrom7893
    • 4 years ago
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    =[1+(n^4+6n^3+11n^2+6n)]^(1/2), that's as far as you can simplify..

  4. anonymous
    • 4 years ago
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    lets try this \[1+n(n+1)(n+2)(n+3)=(n(n+3)+1)^2\] and thefore your answer is \[n(n+3)+1\]

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