Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

How do you find the area of an acute triangle when you're only given the side lengths????

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the expert answer you'll need to create a free account at Brainly

one way is; you can use the law of cosines to find an angle and use that angle in the side*side*sin(angle)/2 formula
the other is to use herons formula
1 Attachment

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

so the area = \[a timesb \times \sin \] of the angle contained between a and b?
then, divided by two
thats right; so if you can find the angle between two sides, you can find the area
okay! Thanks :)
in my picture; base = b; height = a sin(angle) which fits into the normal Area = b*h/2 that you are familiar with

Not the answer you are looking for?

Search for more explanations.

Ask your own question