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anonymous
 5 years ago
hydrogen peroxide can decompose to water and oxygen by the following reaction
2H2O2 (l)  2H2O(l) + O2(g) enthalpy=196kj
calculate the value of q when 5.00g of h20(l) decomposes at constant pressure.
anonymous
 5 years ago
hydrogen peroxide can decompose to water and oxygen by the following reaction 2H2O2 (l)  2H2O(l) + O2(g) enthalpy=196kj calculate the value of q when 5.00g of h20(l) decomposes at constant pressure.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.01 mole of H2O2=34.0148 g 5.00g of H2O2=5/34.0148=0.146995 moles decomposition of 2moles produce 196kj therefore q produced by 0.146995 moles of H2O2=(196/2)*0.146995=14.40551Kj i think this is the way , i hve not been through this calculation for a long period~910years sorry if there is a mistake...........

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the answer is correct...thanx for the explanation
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