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TransendentialPI
 3 years ago
Best ResponseYou've already chosen the best response.1We need a point and a slope to find a linearization. All you are really finding is a y=mx+b First find m Take the derivative of cos x sub in 7pi/2 This value will be the slope for your line Now we need a point We know x = 7pi/2 Use f(x)=cos(x) to find y = f(7pi/2) Then I like to use the pointslope form of the equation of a line \[yy _{1} =m \left( xx _{1} \right) \] Solve for y

rmalik2
 3 years ago
Best ResponseYou've already chosen the best response.0can you show me steps by steps please?

nikvist
 3 years ago
Best ResponseYou've already chosen the best response.0\[f(x)=f(a)+f'(a)(xa)=\cos{\frac{7\pi}{2}}\sin{\frac{7\pi}{2}}\left(x\frac{7\pi}{2}\right)=x\frac{7\pi}{2}\]

TransendentialPI
 3 years ago
Best ResponseYou've already chosen the best response.1derivative of cos(x) = sin(x) sin(7pi/2) = sin(pi/2) = (1) now for the point (7pi/2, ? ) cos(7pi/2) = 0 Then it is just like what nikvist posted. OK?
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