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TransendentialPI Group TitleBest ResponseYou've already chosen the best response.1
Use the chain rule twice.
 3 years ago

sall123 Group TitleBest ResponseYou've already chosen the best response.0
how do u do it
 3 years ago

TransendentialPI Group TitleBest ResponseYou've already chosen the best response.1
derivative of e^u = e^u * du/dx What is the u in this case?
 3 years ago

sall123 Group TitleBest ResponseYou've already chosen the best response.0
would it be (lnx)^2
 3 years ago

TransendentialPI Group TitleBest ResponseYou've already chosen the best response.1
right. what is the derivative of u^2?
 3 years ago

TransendentialPI Group TitleBest ResponseYou've already chosen the best response.1
right 2u * du/dx
 3 years ago

TransendentialPI Group TitleBest ResponseYou've already chosen the best response.1
2lnx * ??
 3 years ago

TransendentialPI Group TitleBest ResponseYou've already chosen the best response.1
just the 1/x, the square is on the "outside"
 3 years ago

sall123 Group TitleBest ResponseYou've already chosen the best response.0
therefore its 2 over x
 3 years ago

TransendentialPI Group TitleBest ResponseYou've already chosen the best response.1
put it all together. e^ln x ^2 * 2ln x * 1/x and clean it up.
 3 years ago

TransendentialPI Group TitleBest ResponseYou've already chosen the best response.1
OK? Gotta go. Good luck with it.
 3 years ago

angela210793 Group TitleBest ResponseYou've already chosen the best response.0
it's e^U
 3 years ago

angela210793 Group TitleBest ResponseYou've already chosen the best response.0
\[=(2\log^2_{x} logx)/x\] I guess....
 3 years ago

guyc Group TitleBest ResponseYou've already chosen the best response.0
Mmmm.... not so sure. Try this: we know d/dx(e^x) = e^x So d/dx(e^(lnx)^2) = e^(lnx)^2 times d/dx(lnx)^2 = e^(lnx)^2 times 2lnx times d/dx(lnx) = e^(lnx)^2 times 2lnx times (1/x)
 3 years ago
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