sall123
Derivative of e^(lnx)^2
Delete
Share
This Question is Closed
TransendentialPI
Best Response
You've already chosen the best response.
1
Use the chain rule twice.
sall123
Best Response
You've already chosen the best response.
0
how do u do it
TransendentialPI
Best Response
You've already chosen the best response.
1
derivative of e^u = e^u * du/dx
What is the u in this case?
sall123
Best Response
You've already chosen the best response.
0
would it be (lnx)^2
TransendentialPI
Best Response
You've already chosen the best response.
1
right. what is the derivative of u^2?
sall123
Best Response
You've already chosen the best response.
0
2u
TransendentialPI
Best Response
You've already chosen the best response.
1
right 2u * du/dx
TransendentialPI
Best Response
You've already chosen the best response.
1
2lnx * ??
sall123
Best Response
You've already chosen the best response.
0
its 1/x^2
TransendentialPI
Best Response
You've already chosen the best response.
1
just the 1/x, the square is on the "outside"
sall123
Best Response
You've already chosen the best response.
0
therefore its 2 over x
TransendentialPI
Best Response
You've already chosen the best response.
1
put it all together. e^ln x ^2 * 2ln x * 1/x and clean it up.
TransendentialPI
Best Response
You've already chosen the best response.
1
OK? Gotta go. Good luck with it.
angela210793
Best Response
You've already chosen the best response.
0
it's e^U
angela210793
Best Response
You've already chosen the best response.
0
\[=(2\log^2_{x} logx)/x\] I guess....
guyc
Best Response
You've already chosen the best response.
0
Mmmm.... not so sure. Try this:
we know d/dx(e^x) = e^x
So d/dx(e^(lnx)^2) = e^(lnx)^2 times d/dx(lnx)^2
= e^(lnx)^2 times 2lnx times d/dx(lnx)
= e^(lnx)^2 times 2lnx times (1/x)