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anonymous
 4 years ago
Derivative of e^(lnx)^2
anonymous
 4 years ago
Derivative of e^(lnx)^2

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Use the chain rule twice.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0derivative of e^u = e^u * du/dx What is the u in this case?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0right. what is the derivative of u^2?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0just the 1/x, the square is on the "outside"

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0therefore its 2 over x

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0put it all together. e^ln x ^2 * 2ln x * 1/x and clean it up.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0OK? Gotta go. Good luck with it.

angela210793
 4 years ago
Best ResponseYou've already chosen the best response.0\[=(2\log^2_{x} logx)/x\] I guess....

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Mmmm.... not so sure. Try this: we know d/dx(e^x) = e^x So d/dx(e^(lnx)^2) = e^(lnx)^2 times d/dx(lnx)^2 = e^(lnx)^2 times 2lnx times d/dx(lnx) = e^(lnx)^2 times 2lnx times (1/x)
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